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GaryK [48]
2 years ago
6

4x(2+3)= A. (6+7) B. (8+12) C. (8 x 12)

Mathematics
1 answer:
professor190 [17]2 years ago
5 0

Answer:

The Answer would be B. (8+12)

Step-by-step explanation: If you do the full equation 4(2+3) you get 20. So therefore, the last step in order to solve would be to add 8+12=20.

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Select all numbers that are solutions to the inequality k>5
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Answer:

its c d and e they're all greater than 5

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If you answer these question I will give you brainiest plus 20 points
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What is the question
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Thomas made 8700mL of tomato soup. He packed 1.6L of the soup in his kids' lunches. He then froze half of the remaining soup. Ho
Nitella [24]

Let's convert the 8700mL to L so that we can use the information in the problem more easily and swiftly. Since 1000mL is the same thing as 1L, we can say that 8700 mL of tomato soup is equal to 8.7L of tomato soup.


First, we know that he removed 1.6L to put in his kids' lunches. Thus, we now have 7.1L remaining. Now, we know that he froze half of this. Half of 7.1L is 3.55L (7.1L/2 = 3.55L), which means that he froze 3.55L. Finally, we will need to convert this back to mL. Since 1L is equal to 1000mL, we can multiply 3.55 by 1000 to get 3550mL.

5 0
4 years ago
Write a function rule for each table.
Nat2105 [25]
Let's assume that this function is linear. 

Take any 2 of the points and find the slope of the line segment connecting them:

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6 0
4 years ago
Read 2 more answers
It is believed that 3% of people actually have this predisposition. The genetic test is 99% accurate if a person actually has th
fiasKO [112]

Answer:

Required Probability = 0.605

Step-by-step explanation:

Let Probability of people actually having predisposition, P(PD) = 0.03

Probability of people not having predisposition, P(PD') = 1 - 0.03 = 0.97

Let PR = event that result are positive

Probability that the test is positive when a person actually has the predisposition, P(PR/PD) = 0.99

Probability that the test is positive when a person actually does not have the predisposition, P(PR/PD') = 1 - 0.98 = 0.02

So, probability that a randomly selected person who tests positive for the predisposition by the test actually has the predisposition = P(PD/PR)

Using Bayes' Theorem to calculate above probability;

 P(PD/PR) = \frac{P(PD)*P(PR/PD)}{P(PD)*P(PR/PD)+P(PD')*P(PR/PD')}

                   = \frac{0.03*0.99}{0.03*0.99+0.97*0.02} = \frac{0.0297}{0.0491} = 0.605 .

7 0
3 years ago
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