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Svet_ta [14]
4 years ago
8

2.) What is the value of x?

Mathematics
1 answer:
Len [333]4 years ago
8 0

Answer:

54

Step-by-step explanation:

add all of the numbers then subtract from 100

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Rewrite 1 3/5 as a decimal number?
Alika [10]
The decimal for 1 3/5 would be 1.6
5 0
3 years ago
Complete the table for the given rule y=x/4
vichka [17]
Since they only give you the y values in the table, it would be easier if you isolated the x in the rule:

y = x/4

Multiply both sides by 4

4y = x

Now you can simply substitute the y values into the rule to get the x

4(4) = 16

4(2) = 8

4(9) = 36

~~hope this helps~~

4 0
3 years ago
How would you solve this?
butalik [34]
Hello,

I suppose as we don't see correctely the 2nd image, that it is the first one.

Angles DOY  and  DKY intersept then same arc are equals.

5x+15=3x+21
==>2x=6
==>x=3 and 5x+15=5*3+15=30°, 3x+21=3*3+21=30°
Angle OYK=15x=15*3=45°
Angle ODK=9x+18=9*3+18=45° =Angle OYK which intersept the same arc.

3 0
3 years ago
Which equation has the solutions x = startfraction negative 3 plus-or-minus startroot 3 endroot i over 2 endfraction? 2x2 6x 9 =
Gennadij [26K]

The quadratic equation which matches given solution is x² + 3x + 3 = 0. Then the correct option is C.

<h3>What is a quadratic equation?</h3>

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

We know that the formula

\rm x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

The solutions are given below.

\rm x = \dfrac{-3 \pm \sqrt3 \iota }{2}

Then

1)  2x² + 6x + 9 = 0, the zeroes of the equation will be

\rm x = \dfrac{-6\pm 6\iota}{4}\\\\x = \dfrac{-3\pm 3 \iota}{2}

2)  x² + 3x + 12 = 0, the zeroes of the equation will be

\rm x = \dfrac{-3\pm \sqrt{39}\iota}{2}

3)  x² + 3x + 3 = 0, the zeroes of the equation will be

\rm x = \dfrac{-3\pm \sqrt3\iota}{2}

4)  2x² + 6x + 3 = 0, the zeroes of the equation will be

\rm x = \dfrac{-6\pm 2\sqrt{3}}{4}\\\\x = \dfrac{-3\pm \sqrt3 }{2}

More about the quadratic equation link is given below.

brainly.com/question/2263981

4 0
2 years ago
What is the multiplication form six to the fourth power to the second power
igomit [66]

Answer:

1679616

Step-by-step explanation:

(6^4)^2

6*6*6*6*6*6= 1296

1296^2 = 1296*1296

= 1679616

hope this helps :)

5 0
3 years ago
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