Using Pythagoras theorem
|AB|*2=|d/2|=(5*2)+12*2
AB*2=25+144
AB=13
D/2= r=6.5cm
tan¥=6.5/5
tan¥=1.3
¥=tan inverse of (1.3)
¥=52.43 degrees
241,864,704 many different passwords are possible.
The total characters of the password is six in which it is given that first character should start with W, X, Y or Z. So the first character can be filled in 4 ways.
For next five characters it can be any letter of the alphabet or any numeric digit so it will be 26 + 10 = 36.
So second, third, fourth, fifth and sixth space can be taken by 36 characters.
Therefore the total no. of passwords will be 4 * 36 * 36 * 36 * 36 * 36 that is equal to 241,864,704.
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In the fourth step, he didn’t put the “negative” sign for 4.
Answer:
c
Step-by-step explanation:
Well since angle 1 and 2 are vertical angles 1=2 , 2=1 angle 3 is congruent to angle 2 which also equals 108* so if I'm not mistaking angle 3=108* also. HOPE THIS HELPS!!!!!! XD
