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notka56 [123]
2 years ago
8

Directions: Review writing expressions to represent situations. Identify the variables,coefficients, and constants.

Mathematics
1 answer:
mojhsa [17]2 years ago
7 0

#1

  • Let the number be x
  • Three times the number means 3x.
  • 8more girls

The expression is

  • 3x+5

#2

  • He began as x
  • Now he has 9 times more

So the expression is

  • 9x

#3

  • Dimes be a
  • Nickel be b
  • Quarter be z

The expression is

  • 3a+b+z

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3 hours in 11 questions help plsssssss !!!!!!!!!!
e-lub [12.9K]

Answer:

regular a polygon is: c, e, a

irregular is: b

not a polygon is f, d

Step-by-step explanation:

Regular is a normal shape which has angles

Irregular has straight lines all the way.

Not a polygon has not straight lines and sometimes has a gap in between the lines.

Hope this helps.

7 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
Solue for a<br> d3a=b<br> 3<br> Please help
laiz [17]

Answer:

{d}^{3} a = b \\   \frac{ {d}^{3}a }{ {d}^{3} }  =  \frac{b}{ {d}^{3} }  \\  \\ { \boxed{ \boxed{a =  \frac{b}{ {d}^{3} } }}}

5 0
3 years ago
BRANILIEST ANSWER GETS ALOT OF POINTS I NEED HELP PLZZ
yulyashka [42]
For this problem, I'd use cross-multiplication.

9/12 = x/8.

When cross multiplying, multiply 12*x and 9*8. This leads to a new equation:

12x = 72.

Then you solve as an algebra problem.

*Divide 12 on both sides*

x = 6.
6 0
3 years ago
Plz help me with this !!
Lubov Fominskaja [6]

Answer:

u have to use the almighty formula

7 0
3 years ago
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