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Korvikt [17]
3 years ago
9

Whats the answer for w^5+4w^4+10w^3+40w^2

Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0

Answer:

w^2*(w+4)*(w^2+10)

Step-by-step explanation:

w^5+4w^4+10w^3+40w^2

w^2*(w^3+4w^2+10w+40)\w^2*(w^2*(w+4)+10(w+4))

w^2*(w+4)*(w^2+10)

EastWind [94]3 years ago
4 0

I'm assuming there's an =0 at the end of this?

You need to factor to get an answer, so:

w^5+4w^4+10w^3+40w^2=0\\w^4(w+4)+10w^2(w+4)=0\\(w^4+10w^2)(w+4)=0\\w^2(w^2+10)(w+4)=0\\w=0\\w^2+10=0\\w^2=-10\\w=\sqrt{-10}=10i\\ w+4=0\\w=-4\\w=0,10i,-4

If your teacher doesn't want any imaginary numbers, then your answer would be limited to w=0 and 4. (exclude the 10i if you don't want imaginary numbers)

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Answer:

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Step-by-step explanation:

The volume of a cylinder is:

V=\pi*r^2*h

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The height is 4 inches greater that the radius, so:

h=r+4in

Substituting this in the formula for volume:

V=\pi*r^2*(r+4)

the volume is V=5\pi in^3

thus:

5\pi in^3=\pi*r^2*(r+4in)

Dividing everything between pi:

5in^3=r^2*(r+4in)

5in^3=r^3*+4r^2

We can see that the solution for this is r=1in

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We have the radius, now we find the height:

h=r+4in=1in + 4in = 5in

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Answer:

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Step-by-step explanation:

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