Whats the answer for w^5+4w^4+10w^3+40w^2

Mathematics

2 answers:

Mazyrski [523]3 years ago

6 0

Answer:

w^2*(w+4)*(w^2+10)

Step-by-step explanation:

w^5+4w^4+10w^3+40w^2

w^2*(w^3+4w^2+10w+40)\w^2*(w^2*(w+4)+10(w+4))

w^2*(w+4)*(w^2+10)

EastWind [94]3 years ago

4 0

I'm assuming there's an =0 at the end of this?

You need to factor to get an answer, so:

$w^5+4w^4+10w^3+40w^2=0\\w^4(w+4)+10w^2(w+4)=0\\(w^4+10w^2)(w+4)=0\\w^2(w^2+10)(w+4)=0\\w=0\\w^2+10=0\\w^2=-10\\w=\sqrt{-10}=10i\\ w+4=0\\w=-4\\w=0,10i,-4$

If your teacher doesn't want any imaginary numbers, then your answer would be limited to w=0 and 4. (exclude the 10i if you don't want imaginary numbers)

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A strip mall in Dallas has store space in several different sizes. There are eight 300-square-foot stores, one 800-square-foot s

Vesna [10]

Answer:

Part 1: "What is the ratio of vacant space to occupied space?" $\frac{6}{35}$

Part 2: "What percent of the space is occupied?" 85.37%

Step-by-step explanation:

1st part:

Total square foot = (8*300) + (1*800) + (1*900) = 4100 sq. feet

Vacant Space = 2*300=600

Occupied Space = 4100 - 600 = 3500

Thus ratio of vacant space to occupied space = $\frac{600}{3500}=\frac{6}{35}$

2nd part:

To find % of occupied space, we need to divide occupied space (in sq ft.) by the total square feet and then multiply by 100 (since we want the percentage):

$\frac{3500}{4100}=0.8537=85.37$

Occupied space is 85.37%

7 0

4 years ago

Step-by-step explanation: Is (5, 5) a solution to the equation y=x ?

enyata [817]

Answer:

Yes, (5,5) is a solution of y=x

Step-by-step explanation:

A point is given as a coordinate pair, (x,y). The first number is x and the second number is y. A solution is a pair of numbers that will make the equation true.

To check if the point is a solution, fill in the first number in place of x in the equation. Then fill in the second number for the y.

Here we have the equation:

y = x

Substituting (filling in) we get:

5 = 5 a true statement. So (5,5) IS a solution.

Alternatively, you could graph the equation and verify that the point is on the graph. see image.