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sveticcg [70]
3 years ago
13

62,53,44,35 find a20

Mathematics
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

a20 = -108

Step-by-step explanation:

53 - 62 = -9

44 - 53  = -9

35 - 44  = -9

Then the intervall is -9

The first number is 63

63 + (19*-9) = 63 - 171 = -108

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Evaluate the expression for x = 5, y = 3, and z = 14 . 5x−6y+20z over 4yz Enter your answer in the box.
spin [16.1K]

Hello from  MrBillDoesMath!


Answer:   1 17/24


Steps:

          Evaluate             (5x-6y+20x)/ 4yz when x = 5, y = 3, z = 14


          (5(5) - 6(3) + 20(14))   / 4 (3)(14)          (Substitute in values)

       = (25   - 18    +280)       / 4 (3) (14)         (Evaluate products)

       =  (287) /  4 (3) (14)                                (Evaluate expressions)

      =  287/ 168                                             (4 (3)(14) = 168)

      =  (168  + 119 ) /168                                 287 = 168  + 119

      = (168)/168 + 119/168

      = 1              + 119/168

      = 1  119/168          

       BUT 119 = 17 * 7  (surprise!)  and 168 = 12 * 7 * 2 so answer

    =  1 (17*7)/(12*7*2)

    =  1 (17)/(12*2)                               (Cancel 7's)

    = 1 (17/24)                                    


Regards, MrB    


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