Answer:
Nitrobenzene < Bromobenzene < Benzene < Phenol
Explanation:
Aromatic compounds undergo electrophilic aromatic substitution reaction in the presence of relevant electrophiles. Certain substituents tend to increase or decrease the tendency of an aromatic compound towards electrophilic aromatic substitution reaction.
Substituents that increase the electron density around the ring such as in phenol tends to make the ring more reactive towards electrophilic substitution. Halogens such as bromine has a -I inductive effect as well as a +M mesomeric effect.
However the -I(electron withdrawing effect) of the halogens supersedes the +M electron donation due to mesomeric effect.
Putting all these together, the order of increasing reactivity of the compounds towards electrophilic aromatic substitution is;
Nitrobenzene < Bromobenzene < Benzene < Phenol
2.3226678127494718
this number you could probably simplify to your own standards on your own.
25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)
<h3>Explanation</h3>
The process:
.
How many moles of this process?
Relative atomic mass from a modern periodic table:
- K: 39.098;
- N: 14.007;
- O: 15.999.
Molar mass of :
.
Number of moles of the process = Number of moles of dissolved:
.
What's the enthalpy change of this process?
for . By convention, the enthalpy change measures the energy change for each mole of a process.
.
The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.
Answer:
Explanation:
Here is an illustration showing how to "calculate" +5 as the effective nuclear charge (Zeff) for phosphorus. We are not implying that the electrons are in orbits here, this is simply showing inner shell electrons that shield the outer valence electrons from the full nuclear charge.
Answer:
Hello, Im Mack. Hope you're doing well. :)
Here is my Correct, custom answer for the lab Question, (I also took the same assignment and got a 100% score)
Explanation:
The heating of the sodium acetate solution made it change from super-saturated to un-saturated. Yet now that it cooled back to room temperature Im sure it is saturated. it wasn't able to disolve the excess sodium acetate left over at room temperature and had to be heated so now that it is back to room temperature I Think it will not disolve the sodium acetate left in the solution until it is heated again.
Hope this helped you out,
Please feel free to comment for further help, and I'll reply asap.
<u>Have a great day my friend :)</u>