(I crossed simplify)
Next cross multiply;
3b = 1
b = 1/3
To check if the statement is true just substitute the value of b in the equation;
3b = 1
3(1/3) = 1
1 = 1
Answer:
Step-by-step explanation:
f'(x)=-sin x
c=0∈(-π/3,π/3)
The limit is the y value that the graph approaches from both sides as x approaches the target limit
it they approach different values from the left and right sides, the limit does not exist
we want to find the limit as x approaches 5
we are given that f(x)=5-x for x<5 and f(5)=8 and f(x)=x+3 for x>5
evaluate them all for f(5)
f(x)=5-x
f(5)=5-5
f(5)=0
f(5)=8
f(x)=x+3
f(5)=5+3
f(5)=8
it approaches 0 and 8 from both sides
the limit doesn't exist
D
If the discriminant(b^2-4ac) is rational, then the quadratic is rational.
~ThePirc
