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steposvetlana [31]
2 years ago
6

Pls help!!!!!!!

Mathematics
1 answer:
mr Goodwill [35]2 years ago
6 0

Answer:

im not smart :D

Step-by-step explanation:

sorry no can do

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PLS HELPPPP MEEEE I NEED WORK SHOWN TOO
Elanso [62]

The series of operations for each case are listed below:

  1. GCF / GCF / GCF
  2. GCF / Grouping
  3. Quadratic trinomial
  4. GCF / Quadratic trinomial
  5. Difference of squares
  6. Difference of cubes / Quadratic trinomial
  7. Sum of cubes
  8. GCF / Quadratic trinomial
  9. GCF / Difference of squares

<h3>How to applying factor properties to simplify algebraic expressions</h3>

In algebra, factor properties are commonly used to solve certain forms of polynomials in a quick and efficient way and whose effectiveness is sustained on all definitions and theorems known in real algebra. In this problem, we should explain and show what factor properties are used in each case:

Case 1

5 · x · y³ + 10 · x² · y                                             Given

5 · (x · y³ + 2 · x² · y)                                            GCF

5 · x · (y³ + 2 · x · y)                                              GCF

5 · x · y · (y² + 2 · x)                                              GCF

Case 2

6 · z · x + 9 · x + 14 · z + 21                                   Given

3 · x · (z + 3) + 7 · (z + 3)                                       GCF

(3 · x + 7) · (z + 3)                                                  Grouping

Case 3

a² + 2 · a - 63                                                       Given

(a + 9) · (a - 7)                                                       Quadratic trinomial

Case 4

6 · z² + 5 · z - 4                                                     Given

6 · [z² + (5 / 6) · z - 2 / 3]                                      GCF

6 · (z - 1 / 2) · (z + 4 / 3)                                         Quadratic trinomial

Case 5

81 · m² - 25                                                           Given

(9 · m + 5) · (9 · m - 5)                                           Difference of squares

Case 6

8 · x³ - 27                                                               Given

(2 · x - 3) · (4 · x² + 6 · x + 9)                                  Difference of cubes

4 · (2 · x - 3) · [x² + (3 / 2) · x + 9 / 4]                      Quadratic trinomial

Case 7

27 · b³ + 64 · z³                                                      Given

(3 · b + 4 · z) · (9 · b² - 12 · b · z + 16 · z²)               Sum of cubes

Case 8

2 · w³ - 28 · w² + 80 · w                                         Given

2 · w · (w² - 14 · w + 40)                                          GCF

2 · w · (w - 4) · (w - 10)                                             Quadratic trinomial

Case 9

200 · a⁴ - 18 · b⁶                                                     Given

2 · (100 · a⁴ - 9 · b⁶)                                                GCF

2 · (10 · a² + 3 · b³) · (10 · a² - 3 · b³)                       Difference of squares

To learn more on polynomials: brainly.com/question/17822016

#SPJ1

7 0
1 year ago
Find the square roots of the following numbers. Give the steps correctly.
Novay_Z [31]

Answer:

the sqare root of 19.9 is 4.46094160464

3 0
3 years ago
I reallllyy neeeeedd helpppp dont be capping put the right answer
Jlenok [28]

I believe it's A, C and D.

7 0
2 years ago
Evaluate the question​
mylen [45]

Answer:

A) 5/6

B) -67/30 (or) -2 7/30

A) -9/2 (or) -4 1/2

Step-by-step explanation:

A) 2/3(5)-5/2=3 1/3-5/2 = 10/3-5/2 = 20/6-15/6= 5/6

B) 2/3(2/5)-5/2= 4/15-5/2 = 8/30-75/30 = -67/30

A) 2/3(-3)-5/2=-2-5/2= -4 1/2

7 0
2 years ago
M(x)=−(x−5) 2 +25m, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 5, right parenthesis, squ
Aleksandr [31]

Answer:

25

Step-by-step explanation:

Given the function that represents the amount of mosquitoes as;

M(x) = -(x-5)² + 25

To get the maximum mosquitoes possible, we need to first find x;

At the maximum dM/dx = 0

dM//dx = -2(x-5)

0 = -2(x-5)

-2(x-5) = 0

-2x + 10 = 0

-2x = -10

x = 10/2

x = 5

Substitute x = 5 into the function;

M(5) = −(5−5)² +25

M(5) = 0+25

M(5) = 25

Hence the maximum number of mosquitoes is 25

8 0
2 years ago
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