Answer:
Step-by-step explanation:
In
O, ST and VT are tangents at points S and V respectively.
In quadrilateral OSTV,
(By interior angle sum postulate of a quadrilateral)
(Measure of minor arc is equal to measure of its corresponding central angle)
(By arc sum property of a circle)
![\huge \orange {\boxed {\therefore a =202\degree}}](https://tex.z-dn.net/?f=%5Chuge%20%5Corange%20%7B%5Cboxed%20%7B%5Ctherefore%20a%20%3D202%5Cdegree%7D%7D%20)
3s(s-8)=0
3s = 0 s-8 =0
s=0 s= 8
<em>Answer:</em>
<em>63°</em>
<em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>ABCD parallelogram => ∡A = ∡C</em>
<em>13x - 41 = 6x + 15</em>
<em>13x - 6x = 15 + 41</em>
<em>7x = 56</em>
<em>x = 56 : 7</em>
<em>x = 8</em>
<em>∡C = 6×8 + 15 = 48 + 15 = 63°</em>
<em>Good luck !</em>
Answer:
4 dollars
Step-by-step explanation:
Answer:
3) = A+ D 4)= A and C
Step-by-step explanation: