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SSSSS [86.1K]
2 years ago
13

What’s the circumference of a circle with a diameter of 25 inches? Use 3.14 for pie

Mathematics
2 answers:
mojhsa [17]2 years ago
7 0

Answer:

\star \: \red{circumference _{(circle)} = \pi \: d}

\star \:  \red{circumference _{(circle)} = 3.14 \times 25 inches}

\star \: \red{circumference _{(circle)} = 78.5 inches}

\blue{\frak{saraaaaaaaaahhhh}}

Kipish [7]2 years ago
5 0

Answer:

Circumference=78.5inches

Step-by-step explanation:

Solution,\\Diameter=25 inches\\Now,\\Circumference=\pi d\\Circumference=3.14*25inches=78.5inches

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Which function could be represented by the graph on the coordinate plane?
spin [16.1K]

Answer:

\boxed{f(x)=(x-8)^2-6}

Step-by-step explanation:

The graph in the attachment is a quadratic function whose vertex is in the fourth quadrant.

The coordinates of a point in the fourth quadrant is of the form (x,-y)

Considering the options, the vertex must have coordinates (h,k)=(8,-6) and a=1.


The quadratic function in vertex form is written as;

f(x)=a(x-h)^2+k

Therefore the equation of the quadratic function is;

f(x)=(x-8)^2-6


The correct answer is option D


8 0
3 years ago
What is the gcf of 42 and 56<br><br><br> What is the gcf of 42 and 56
Sholpan [36]

[ Answer ]

14

[ Explanation ]

The GCF is the greatest number that goes into two numbers. 14 is the greatest number that goes into both 42 and 56 evenly.

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6 0
3 years ago
Read 2 more answers
(Giving brainliest and 30 points)
g100num [7]

The price of 1 paint set before the sale is $4.79

Sure hope this helps you

5 0
1 year ago
Read 2 more answers
One half of a number increased by 3 is five less than two thirds of the number
MAVERICK [17]

Answer:

12 is thy number lol

Step-by-step explanation:

1/2x + 3 = 5 - 2/3x  

Subtract the 1/2x

You get 3 = 5 - 1/6x

Subtract the five.

-2 = -1/6x

Multiply by -6

x = 12

6 0
3 years ago
Read 2 more answers
What is the smallest positive integer for x so that f(x)=200(2)* is greater than the value of g(x)=500x+400?
Goshia [24]
We have to functions, namely:

f(x)=200(2)^{x} \ and \ g(x)=500x+400

So the problem is asking for the smallest positive integer for x so that f(x) is greater than the value of g(x), that is:

f(x)\ \textgreater \ g(x) \\ \therefore 200(2)^{x}\ \textgreater \ 500x+400

Let's solve this problem by using the trial and error method:

for \ x=1 \\f(1)=400 \\ g(1)=900 \\ Then \ f(1) \ \textless \ g(1) \\ \\ \\ for \ x=2 \\f(2)=800 \\ g(2)=1400\\ Then \ f(2)\ \textless \ g(2) \\ \\ \\ for \ x=3 \\f(3)=1600 \\ g(3)=1900 \\ Then \ f(3)\ \textless \ g(3) \\ \\ \\ for \ x=4 \\f(4)=3200 \\ g(4)=2400 \\ \boxed{Then \ f(4)\ \textgreater \ g(4)}

So starting x from 1 and increasing it in steps of one we find that:

f(x)>g(x)

when x=4

That is, the smallest positive integer for x so that the function f(x) is greater than g(x) is 4.
8 0
3 years ago
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