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3 years ago

Two thirds of a number, decreased by thirty six, is at most twenty two. Find the number.

1 answer:

6 0

2/3*x-36< or equal 22
2/3*x< or equal 22+36
2/3*x < or equal 58
x < or equal 58:2/3
x < or equal 58*3/2
x < or equal 29*3
x < or equal 87

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PLEASE HELP ME ASAP!! I had trouble with this and it is now over due

erica [24]

Answer:

Shira: x = 8

Samuel: m = 0

Step-by-step explanation:

Shira's mistake was that she subtracted 2 from both sides instead of adding to on both sides.

Correct Solving:

2x - 2 = 14

Add 2 to both sides;

2x = 16

Divide both sides by 2;

x = 8

Samuel's mistake was that when he distributed -2 to 8m and 8 he put the wrong sign for -2 * 8.

Correct Solving:

-2(8m + 8) = -16

Distribute;

-16m - 16 = -16

Add 16 to both sides;

-16m = 0

Divide both sides by -16;

m = 0

3 0

3 years ago

"if n balls are distributed randomly into k urns, what is the probability that the last urn contains j balls?"

seraphim [82]

The answer relies on whether the balls are different or not. If they are not, which is almost certainly what is intended.

If they are, the perceptive is a bit different. Your expression gives the likelihood that a particular set of j balls goes into the last urn and the other n−j balls into the other urns. But there are (nj) different possible sets of j balls, and each of them the same probability of being the last insides of the last urn, so the total probability of completing up with exactly j balls in the last urn is if the balls are different.

See attached file for the answer.

3 0

3 years ago

Answer true or false for 1-10 (picture above)

Softa [21]

$\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a+b}\leq\sqrt{a}+\sqrt{b}\\\\\sqrt{a-b}\geq\sqrt{a}-\sqrt{b}\\----------------------\\1)\ \sqrt{72}=\sqrt{9\cdot8}=\sqrt{9}\cdot\sqrt{8}\qquad TRUE\\\\2)\ \sqrt{13-5}=\sqrt{13}-\sqrt5\qquad FALSE\\\\3)\ \sqrt{9\cdot10}=\sqrt9+\sqrt{10}\qquad FALSE\\\\4)\ \sqrt{18bx}=\sqrt{18}\cdot\sqrt{b}\cdot\sqrt{x}\qquad TRUE\ if\ b\geq0\ and\ x\geq0\\\\5)\ \sqrt{8\cdot12}=\sqrt8\cdot\sqrt{12}\qquad TRUE\\\\6)\ \sqrt{m+x}=\sqrt{m}+\sqrt{x}\qquad FALSE$

$7)\ \sqrt{100+64}=\sqrt{100}+\sqrt{64}\qquad FALSE\\\\8)\ \sqrt{30}=\sqrt{5\cdot6}=\sqrt5\cdot\sqrt6\qquad TRUE\\\\9)\ \sqrt{44}=\sqrt{22+22}=\sqrt{22}+\sqrt{22}\qquad FALSE\\\\10)\ \sqrt{10\cdot10}=\sqrt{10}\cdot\sqrt{10}\qquad TRUE$

3 0

3 years ago

Find the zeros of x^2+4x=-10 using the quadratic formula

ipn [44]

X^2+4+10=0
x=(-4(+/-)root16-40)/2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is -24
so the two roots are…
-2+iroot6 and -2-iroot6

7 0

3 years ago

Read 2 more answers

Ellie borrows money at a year simple rate of 6 1/2% after 4 years ellie owes 39 interest

kupik [55]

Answer: Ellie borrowed $150.

Step-by-step explanation:

I = PRT

39 = P x 0.065 x 4

39 = P x 0.26

Divide both sides by 0.26

150 = P