The range would consist of all real numbers EXCEPT for zero
(x-5) = 0 or (x+2)=0
so x could be 5 or -2
i guess, u can check it with calculator
Step-by-step explanation:
v=6t-6
integrating
s= 3t^2 -6t +k
5=3(1)^2 -6(1) +k
5-3+6=k
k=8
s(t) = 3t^2 -6t +8
12x-2 I think that’s right I’m not really sure