After every month's withdrawals, 4/5 of the original amount at the start of the month will remain. The amount at the start of every month will change. Thus:
an = 4/5 (an-1) ; where a1 = 500.
Answer:
(
−
∞
,
∞
)
Step-by-step explanation:
The value of the function (f.h)(x) is 96x⁵ + 132x⁴ + 78x³ + 18x²
<h3>How to solve function?</h3>
f(x) = 3x² + 4x³ + 8x⁴
g(x) = -3x + 12x² - 5x³
h(x) = 12x + 6
Therefore,
(f.h)(x) = f(x).h(x)
Hence,
f(x).h(x) = (3x² + 7x³ + 8x⁴)(12x + 6)
f(x).h(x) = 36x³ + 18x² + 84x⁴ + 42x³ + 96x⁵ + 48x⁴
(f.h)(x) = 96x⁵ + 84x⁴ + 48x⁴ + 36x³ + 42x³ + 18x²
(f.h)(x) = 96x⁵ + 132x⁴ + 78x³ + 18x²
learn more on function here: brainly.com/question/7783704
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y = abˣ
20 = ab¹
20 = ab
b b
20/b = a
y = abˣ
4 = (20/b)b²
4 = 20b
20 20
¹/₅ = b
y = abˣ
20 = ¹/₅b¹
20 = ¹/₅b
¹/₅ ¹/₅
100 = b
y = abˣ
y = 100(0.2)ˣ
No it is not , it is less than 9/10.