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AleksAgata [21]
3 years ago
10

Need help with number 9

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Step-by-step explanation:

v=6t-6

integrating

s= 3t^2 -6t +k

5=3(1)^2 -6(1) +k

5-3+6=k

k=8

s(t) = 3t^2 -6t +8

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How do you do question b?
notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\

-----------------

This means,

\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\

is the solution with the initial condition y(0) = 0.

6 0
3 years ago
What is 1/2 of 14? this is an algebraic expression!!
Vikentia [17]
1/2 of 14 is 7. multiply 14/1 to 1/2.
3 0
2 years ago
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
What’s the linear equation for (1,21)(2,33)(3,45)(4,57)
nalin [4]

The linear equation representing the above said pair of points is "y=12x+9"

Step-by-step explanation:

The given set of points are  

x Y

1 21

2 33

3 45

4 57

For finding the linear equation for the given sets of value

We must know the generic form of a linear equation is y=m*x + c

m= slope of the line where y= Δy/Δx  

Δy= change in y value

Δx= change in x value

Thus slope ”m” = 33-21/2-1 = 12

we put slope “m” in the equation which becomes y=12x+c

Now we put any of the set value in the equation

33= 12*2+c ∴ c=9

Hence required linear equation is y=12x+9

7 0
3 years ago
Find the area of this circle use 3.14 or 22/7 or pie round your answer to the nearest hundred if necessary
notka56 [123]

Answer:

The area of the circle is 50.24 mm ²

Step-by-step explanation:

To solve this exercise we need to use the area formula of a circle:

a = area

r = radius = 4mm

π = pi = 3.14

a = π * r²

a = 3.14 * (4mm )²

a = 3.14 * 16mm ²

a = 50.24 mm ²

The area of the circle is 50.24 mm ²

6 0
3 years ago
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