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3 years ago

Need help with number 9

Mathematics

1 answer:

beks73 [17]3 years ago

7 0

Step-by-step explanation:

v=6t-6

integrating

s= 3t^2 -6t +k

5=3(1)^2 -6(1) +k

5-3+6=k

k=8

s(t) = 3t^2 -6t +8

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How do you do question b?

notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

$\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\$

-----------------

This means,

$\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\$

is the solution with the initial condition y(0) = 0.

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3 years ago

What is 1/2 of 14? this is an algebraic expression!!

Vikentia [17]

1/2 of 14 is 7. multiply 14/1 to 1/2.

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2 years ago

Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any

alukav5142 [94]

Answer:

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

Step-by-step explanation:

We are given that a differential equation

$(x^2+10)y'+xy-4x=0$

We have to find the general solution of given differential equation

$y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0$

$y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}$

Compare with

$y'+P(x) y=Q(x)$

We get

$P(x)=\frac{x}{x^2+10}$

$Q(x)=\frac{4x}{x^2+10}$

I.F= $e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}$

$e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C$

$y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C$

$y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C$

$y(x)=4+\frac{C}{\sqrt{x^2+10}}$

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3 years ago

What’s the linear equation for (1,21)(2,33)(3,45)(4,57)

nalin [4]

The linear equation representing the above said pair of points is "y=12x+9"

Step-by-step explanation:

The given set of points are

x Y

1 21

2 33

3 45

4 57

For finding the linear equation for the given sets of value

We must know the generic form of a linear equation is y=m*x + c

m= slope of the line where y= Δy/Δx

Δy= change in y value

Δx= change in x value

Thus slope ”m” = 33-21/2-1 = 12

we put slope “m” in the equation which becomes y=12x+c

Now we put any of the set value in the equation

33= 12*2+c ∴ c=9

Hence required linear equation is y=12x+9

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3 years ago

Find the area of this circle use 3.14 or 22/7 or pie round your answer to the nearest hundred if necessary

notka56 [123]

Answer:

The area of the circle is 50.24 mm ²

Step-by-step explanation:

To solve this exercise we need to use the area formula of a circle:

a = area

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a = π * r²

a = 3.14 * (4mm )²

a = 3.14 * 16mm ²

a = 50.24 mm ²

The area of the circle is 50.24 mm ²

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3 years ago