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tangare [24]
3 years ago
12

Given two points on the graph of the line, the equation of the line can be found.

Mathematics
2 answers:
ziro4ka [17]3 years ago
7 0
The answer would,be true have a nice day.
harkovskaia [24]3 years ago
3 0
The answer is true.
Really all you ever need is two points and you should find an equation.
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Can someone please answer this question please I need it right now and please answer it correctly please show work answer number
schepotkina [342]

Answer:

24) A

22) B

Step-by-step explanation:

24)

Original Price: d      

Sale: 30%    

A sale means that a value is subtracted from the original price

d - 30% = 0.7d

All options given:

A) 0.3d

B) 0.7d

C) d - 0.3d = 0.7d

D) (1.0 - 0.3)d = 0.7(d) = 0.7d

All of these options are equal to the price after the sale, except A.

A is the answer to question 24

22)  m > 0, n > 0    Use an example to represent m and n

m = 1,  n = 2 = -0.5

-0.5 is a rational, negative number

The answer to question 22 is B

Hope this helps :)

5 0
2 years ago
Write the number name and expanded form for 710,231​
vekshin1

Answer:

seven hundred ten and two hundred and thirty one 700,000+ 10,000+ 200+30+1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST FOR 1 ALGEBRA QUESTION!!!
irinina [24]

Answer:

x=4, y=3

Step-by-step explanation:

6 0
3 years ago
if you flip a coin 10 times, what is the best prediction​ possible for the number of times it will land on heads?
SVETLANKA909090 [29]
Proabably. 5 because if there is 2 sides on a coin then you should divide 10÷2 which is 5.
4 0
3 years ago
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Solve the following equation. X cubed minus 6X squared plus 6X equals zero
anyanavicka [17]

We have to solve this equation:

x^3-6x^2+6x=0

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}

Now we can find the roots of the quadratic polynomial as:

\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0
1 year ago
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