All categories

2 years ago

Give a pair of corresponding angles, a pair of alternate interior angles, and a pair of alternate exterior angles

Mathematics

1 answer:

nataly862011 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

<2 and <8 are alternate exterior angles

<4 and <6 are alternate interior angles

<3 and <6 are corrosponding angles

You might be interested in

What is the domain of the piecewise function?

Anastaziya [24]

Answer:

C. All real numbers

4 0

2 years ago

Please help! "Indicate the equation of the given line in standard form. The line containing the midpoints of the legs of right t

julsineya [31]

Nice. We're not really told which is the right angle. We can tell from the squared distances:

$AB^2=(1 - -5)^2 + (1-5)^2=6^2+4^2=52$

$BC^2=(3-1)^2+(4-1)^2=2^2+3^2=13$

$AC^2=(3- -5)^2+(4 -5)^2=8^2+1^2=65$

We see $AC^2=AB^2+BC^2$ so B is the right angle.

That was preliminary and probably indicated in an associated figure.

Now we want the line through the midpoint of the legs, AB and BC, in standard form.

The midpoint of AB is the average of the coordinates of A and B:

$\left( \dfrac{-5 +1}{2}, \dfrac{5+1}{2} \right) = (-2,3)$

The midpoint of BC is

$\left( \dfrac{1 + 3}{2}, \dfrac{1 + 4}{2} \right) = ( 2, \frac 5 2)$

The line through those points is

$(y - 3)(2 - -2)=(x - -2)(\frac 5 2 - 3)$

$4y - 12 = (x+2)(- \frac 1 2)$

$8y - 24 = -x -2$

$x + 8y = 22$

That's the answer. Let's check it.

Midpoint of AB is (-2,3), -2 + 8(3)=22 good.

Midpoint of BC is (2,5/2), 2+8(5/2)=22 good.

$\textrm{Answer: } x + 8y = 22$

4 0

4 years ago

777×900<br>Can u help me

Brums [2.3K]

1st Answer:

The answer to this would be 699,300!

Have a great day good luck! Plugging it into a calculator was easy^^

4 0

3 years ago

Read 2 more answers

Each student must sell 2 different types of raffle tickets to raise $18. The raffle ticket to win a book costs $2. The raffle ti

gogolik [260]

Answer:

9 of the 2 dollar ticket and 6 of th 1.50 dollar ticket.

7 0

3 years ago

Each side of a square is increasing at a rate of 8 cm/s. At what rate (in cm2/s) is the area of the square increasing when the a

statuscvo [17]

Answer:

Step-by-step explanation:

This is nice and simple. I'm going to walk through it like I do when teaching this concept to my class for the first time. This is a good problem for that.

We are given a square and we are looking for the rate at which the area is increasing when a certain set of specifics are given. That means that the main equation for this problem is the area of a square, which is:

$A=s^2$ where s is a side.

Since we are looking for the rate at which the area is changing, $\frac{dA}{dt}$ , we need to take the derivative of area formula implicitly:

$\frac{dA}{dt}=2s\frac{ds}{dt}$ that means that if $\frac{dA}{dt}$ is our unknown, we need values for everything else. We are given that the initial area for the square is 49. That will help us determine what the "s" in our derivative is. We plug in 49 for A and solve:

$49=s^2$ so

s = 7

We are also given at the start that the sides of this square are increasing at a rate of 8cm/s. That is $\frac{ds}{dt}$ . Filling it all in:

$\frac{dA}{dt}=2(7)(8)$ and

$\frac{dA}{dt}=112\frac{cm^2}{s}$

5 0

3 years ago

Read 2 more answers