The equation of the plane that goes through these points is:
6x + 2y + z = 10.
<h3>How to find the equation of a plane given three points?</h3>
The equation of the plane is found replacing the points into the following equation:
ax + by + c = z.
For point A, we have that:
3b + c = 4.
For point B, we have that:
a + 2b + c = 0.
For point C, we have that:
-a + 6b + c = 4.
Hence the system is:
From the first equation, we have that:
c = 4 - 3b.
Replacing in the second, we have that:
a + 2b + 4 - 3b = 0
a - b = -4.
Replacing in the third, we have that:
-a + 6b + 4 - 3b = 4.
-a + 3b = 0.
a = 3b.
We have that a - b = -4, hence:
3b - b = -4
2b = -4
b = -2.
a = 3b, hence a = -6.
c = 4 - 3b -> c = 10.
Hence the equation is:
ax + by + c = z.
z = -6x - 2y + 10
6x + 2y + z = 10.
More can be learned about the equation of a plane at brainly.com/question/13854649
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Simplify it to 2x-4=8x-4
-6x=0
x=0
not sure if that counts as no solution or single solution though...
Answer:
KL= 63
Step-by-step explanation:
JK=7x+9 , JL=114 , KL=9x+9 ( if the points are on the same line and point J at the end point and K in the middle)
*J_______________________K___________________________L
JL=JK+KL
114=7x+9+9x+9
114-18=16 x
16x=98
x=98/16=6
KL= 9x+9
KL=9(6)+9
KL= 63
The answer is -4 for it to be translated right.
Answer:
Step-by-step explanation:
opposite= 8 : the length opposite angle c
adjacent=15 : the length next to angle c, not the hypotenuse
hypotenuse= 17 : the hypotenuse will always be opposite the right angle
