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2 years ago

5

The graph of f(x)=cos(x) is transformed to a new function, g(x), by stretching it horizontally by a factor of 4 and shifting it

1 unit up.
What is the equation of the new function g(x)?

1 answer:

pshichka [43]2 years ago

4 0

I hope this helps you :)

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The cable company is analyzing data from two satellite television providers to determine whether their users spend more time wat

Phoenix [80]

Answer:

59%

Step-by-step explanation:

The information from Satellite Company Y is:

65 people watch live and 94 people watch recorded.

The total number of people from Y is:

65 + 94 = 159

So the probability that a random person from Y watches recorded shows more often is given by the division of the number of people watching more recorded shows (94) over the total number of people (159):

Probability = 94 / 159 = 0.5912 = 59.12%

Rounding to nearest whole percent, we have 59%

3 0

3 years ago

Read 2 more answers

What is the sum of the zeros of the function: y= x^2 - 5x + 6?

yawa3891 [41]

Answer:

Step-by-step explanation:

The zeros are the values of x for which y = 0

Quadratic formula

x = [5 ± √(5² – 4·1·6)] / [2·1]

= [5 ± √1] / 2

= [5 ± 1] /2

= 2, 3

sum of zeros = 5

7 0

3 years ago

Charlie ran 5 miles in 51.5 minutes. Use the equation 5r=51.5 to find r, the average rate he ran.

jenyasd209 [6]

5r = 51.5
r = 51.5 / 5
r = 10.3

6 0

3 years ago

Read 2 more answers

A)180.48 m2<br><br> B)180.48 m<br><br> C)80.48 m2<br><br> D)80.48 m

MissTica

Answer:

80.48m2

Step-by-step explanation:

I think this is right but it may be wrong.

4 0

2 years ago

The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?

AleksAgata [21]

Answer:

$\large \boxed{2}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

$\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}$

Check:

$\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}$

It checks.

7 0

3 years ago