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Nastasia [14]
3 years ago
6

Which fraction is closer to 0 than 1​

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

5/12

Step-by-step explanation:

Since 1/2 is the same distance from zero and one, we can use it to judge whether a fraction is closer to 0 or 1.

Since 5/8 is greater than 4/8 which is 1/2, it is closer to 1.

Since 8/10 is greater than 5/10 which is 1/2, it is closer to 1.

Since 5/12 is less than 6/12 which is 1/2, it is closer to 0.

So our answer is C. 5/12

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Solve for b. ab+c=d. 1.b=a+c/d 2.b=a/(c-d) 3.b=(d-c)/a
amm1812

Answer:3

Step-by-step explanation:

8 0
2 years ago
Solve the following by elimination method <br> 11x+15y+23=0 and 7x-2y-20=0
mr Goodwill [35]
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]

Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3

Therefore, x = 2 and y = -3.
7 0
3 years ago
NO LINKS OR FILES. Explain how to evaluate 5p + (-6) when p = -4. Please give an explanation.
alexdok [17]

Answer:

-26

Step-by-step explanation:

5p + (-6)

Let p=-4

5(-4) + (-6)

Multiply

-20 +-6

Add

-26

8 0
2 years ago
Read 2 more answers
3/5(4.3 – 7.8) + 2 1/9 ?
True [87]

Answer:

0.01

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which of the following is an improper integral?
guapka [62]

Answer:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

  • Removable (Hole)
  • Jump
  • Infinite (Asymptote)

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C
  • Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

B)  \displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx

C)  \displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integration

Book: College Calculus 10e

6 0
3 years ago
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