5x6-1+3=28 brackets or braces should be added

A composite figure is shown.

VikaD [51]

The surface area of the pyramid is 60 square feet

The surface area of the square prism is 480 square feet

The surface area of the cube is 180 square feet

The total surface area is 720 square feet

<h3>Area of Composite figures</h3>

From the question, we are to calculate the surface area of each part of the composite figure

For the cube

Surface area of a cube is given by

$S = 6l^{2}$

Where $l$ is the length of a side

But only have 5 surfaces of the cube are part of the composite figure

∴ Surface area of the cubic part of the figure = $5l^{2}$

From the given information,

$l = 6 \ feet$

∴ Surface area of the cubic part of the figure = 5 × 6²

Surface area of the cubic part of the figure= 180 square feet

For the square prism

The surface area of a square prism is given by the formula,

$S = 2l^{2} + 4lh$

Where $l$ is the length of the sides and

$h$ is the height

But the <u>square surfaces</u> are not part of the surface of the figure

∴ Surface area of the square prism in the figure = $2l^{2} + 4lh - 2l^{2}$

Surface area of the square prism in the figure = $4lh$

From the given information,

$l = 6 \ feet$

$h = 20 \ feet$

Thus,

Surface area of the square prism part of the figure = 4×6×20

Surface area of the square prism part of the figure = 480 square feet

For the pyramid

The pyramid is a square pyramid

The surface area of a square pyramid is given by

$S = l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h ^{2} }$

Where $l$ is the base length

and $h$ is the height of the prism

But the <u>square base</u> is not part of the surface of the figure

∴ Surface area of the pyramid part of the figure = $l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h^{2} }\ - ( l^{2})$

Surface area of the pyramid part of the figure = $2l\sqrt{\frac{l^{2} }{4}+h^{2} }$

From the given information,

$l = 6 \ feet$

$h = 4 \ feet$

∴ Surface area of the pyramid part of the figure = $2(6)\sqrt{\frac{6^{2} }{4}+4^{2} }$

= $12\sqrt{\frac{36 }{4}+16}$

= $12\sqrt{9+16 }$

= $12\sqrt{25}$

= 12 × 5

= 60 square feet

Hence, the surface area of the pyramid is 60 square feet

Thus,

The total surface area = 180 square feet + 480 square feet + 60 square feet

The total surface area = 720 square feet

Hence, the total surface area is 720 square feet

Learn more on Calculating area of composite figures here: brainly.com/question/13175744

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4 0

2 years ago

100 points!!!! To whoever helps me with this!

netineya [11]

Answer:

#1: Josue's dogs

#2: see images

#3: Am group median: 25.5 Pm group median: 19

#4: Am group first Quartile = 16 Pm group first Quartile = 10

#5: Am group third Quartile = 30 Pm group third Quartile = 37

#6: see images

#7: Am group Interquartile Range = 14 Pm group Interquartile Range = 27

#8: Am group because its Interquartile gruop is smaller than the Pm group

Step-by-step explanation:

Mark as Brainliest

5 0

3 years ago

Read 2 more answers

3/2 x 7/8 = <br><br><br> Simplify if needed:

Svetach [21]

Answer:

3/2 x 7/8 = (3×7)/(2×8)=21/16

4 0

3 years ago

Read 2 more answers

The rectangle below has an area of 70y^8+30y^6.The width of the rectangle is equal to the greatest common monomial factor of 70y

swat32

Answer:

Width $10y^6$ units

Length $7y^2+3$ units

Step-by-step explanation:

The rectangle has an area of $70y^8+30y^6.$

The width of the rectangle is equal to the greatest common monomial factor of $70y^8$ and $30y^6.$ Find this monomial factor:

$70y^8=2\cdot 5\cdot 7\cdot y^8\\ \\30y^6=2\cdot 3\cdot 5\cdot y^6\\ \\GCF(70y^8,30y^6)=2\cdot 5\cdot y^6=10y^6$

Hence, the width of the rectangle is $10y^6$ units.

The area of the rectangle can be rewritten as

$10y^6(7y^2+3).$

The area of the rectangle is the product of its width by its length, then the length of the rectangle is $7y^2+3$ units.

8 0

3 years ago

Is a function y = 4x + 13

tankabanditka [31]

Answer:

Yes

Step-by-step explanation:

7 0

3 years ago