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Ierofanga [76]
4 years ago
7

Two trains are 480 miles apart. They start at the same time, and travel towards one another. The difference between the speeds o

f the two train is 20 miles per hour. If the two trains meet after four hours, find the speed of the faster train. can someone explained this please
Mathematics
1 answer:
Genrish500 [490]4 years ago
5 0

Answer:

Did you just start today? It looks like you're new here. I'm also new here.

Step-by-step explanation:

I don't really know what to do either.

From what I've done so far, I don't understand it.

Sorry.

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Solve the system by substitution.<br> - 2x – 10y = -2<br> -4y = x
mihalych1998 [28]

Answer:

x = -4 and y = 1

Step-by-step explanation:

hope this helps please like and mark as brainliest

4 0
3 years ago
How do the expressions 8+k2−6 and 8(k+2)−4k compare when k = 7?
Andreas93 [3]

Answer:

8+k2-6>8(k+2)-4k

Step-by-step explanation:

8+7×2-6 and 8(7+2)-4×7

8+14-16 and (56+16)-28

6 and 44

8 0
3 years ago
Can someone please help me with numbers 1, a, b, c, 2, a, b, c
algol [13]
Thank you thank you very much
7 0
3 years ago
The width of a rectangle is 18 meters less than twice the length, x. The width of the rectangle is 68 meters. Which equation can
Morgarella [4.7K]

Answer:

None of the options are correct, as the answer is <u>2x - 18 = 68.</u>

Step-by-step explanation:

The <u>2x</u> represents the length (x) being half of the width (68)

The <u>-18</u> represents the width (68) being 18 less than twice the length (2x)

8 0
3 years ago
The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi
inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.        

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

\displaystyle\frac{dr}{dt} = -7\text{ inch per second}

The volume is decreasing at a constant rate.

\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

V = \displaystyle\frac{1}{3}\pi r^2 h

Instant volume =

525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}

Differentiating with respect to t,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)

Putting all the values, we get,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0
3 years ago
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