1.<AFC
2.<AFD
3.<AFE
4.<AFB
#5, 6 and 7
m<BAE = 59
m<BAC + m<CAD + m<DAE = m<BAE
4x - 20 + x + 12 + x + 1 = 59
6x - 7 = 59
6x = 59 + 7
6x = 66
x = 11
m<BAC = 4x - 20 = 4(11) - 20 = 24
m<CAD = x + 12 = 11 + 12 = 23
m<BAE = x + 1 = 11 + 1 = 12
answer
5.
m<BAC = 24
6.
m<CAD = 23
7.
m<BAE = 12
#8, 9 and 10
m<BAE = 130
m<BAC + m<CAD + m<DAE = m<BAE
3x - 10 + 2x + 5 + x + 15 = 130
6x + 10 = 130
6x = 120
x = 20
m<BAC = 3x - 10 = 3(20) - 10 = 60 -10 = 50
m<CAD = 2x + 5 = 2(20) + 5 = 40 + 5 = 45
m<DAE = x + 5 = 20 + 15 = 35
answer
8.
m<BAC = 50
9.
m<CAD = 45
10.
m<DAE = 35
Answer:
6-pack for 3.12
Step-by-step explanation:
Find unit price
2.24/4=0.56
3.00/3=1
4.24/8=0.53
3.12/6=0.52
Step-by-step explanation:
Since Angle DAE = Angle BCE, lines AD amd BC are parallel (by Z-angles).
This means that Angle ADE = Angle CBE (by Z-angles).
We have 2 congruent angles and 1 congruent side (AD = BC, given).
By ASA congruence, triangles AED and CEB are congruent.
Answer:
x = 84°
Step-by-step explanation:
180 - 143 = 37
37 + 59 = 96
180 - 96 = 84°
