All categories

2 years ago

ASAP HELP This is due today so answer correct and I have attempt to do your best

Mathematics

1 answer:

Kamila [148]2 years ago

5 0

Answer:

3) x-axis: 1 unit

y-axis: 10 units

4) quadrant II

coordinates: (-2, 4)

7) Quadrants I and IV; time is always positive , but temperature can be positive and negative

8) W = (-0.75, -1)

Step-by-step explanation:

3) x-axis: 1 unit

y-axis: 10 units

4) quadrant II

coordinates: (-2, 4)

7) Quadrants I and IV; time is always positive , but temperature can be positive and negative

8) W = (-0.75, -1)

You might be interested in

Jenn has 13 fewer marbles then Marty.she has 20 marbles.which equation can be solved to find how many marbles Marty has?

faust18 [17]

If jenn has 13 fewer marbles than marty and we know she has 20 marbles, you would add 13 to 20 (33) to find how many marbles marty has. the equation would be 13+20=33 (or any variable depending on the context of the question.)

6 0

4 years ago

PLEASE HELP ME!!!

allsm [11]

Answer: 25??

Step-by-step explanation: $8×25= $200

i dont know if thats your answer thats just all the adults that could get in for $200.

-Zoey Lee

<h2 />

7 0

3 years ago

Identify the standard form of the equation by completing the square.

OLEGan [10]

Answer:

$\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Step-by-step explanation:

<u>Given equation</u>:

$4x^2-9y^2-8x+36y-68=0$

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

$\implies 4x^2-8x-9y^2+36y=68$

Factor out the coefficient of the x² term and the y² term.

$\implies 4(x^2-2x)-9(y^2-4y)=68$

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

$\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2$

$\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36$

Factor the two perfect trinomials on the left side:

$\implies 4(x-1)^2-9(y-2)^2=36$

Divide both sides by the number of the right side so the right side equals 1:

$\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}$

Simplify:

$\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1$

Therefore, this is the standard equation for a horizontal hyperbola with:

center = (1, 2)
vertices = (-2, 2) and (4, 2)
co-vertices = (1, 0) and (1, 4)
$\textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}$
$\textsf{Foci}: \quad (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)$