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Andrew [12]
3 years ago
9

Please see attached image and help with these absolute value problems - thank you

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

{-infinity, infinity}

no solution

Step-by-step explanation:

|x| +15≥4

Subtract 15 from each side

|x| +15-15≥4-15

|x| ≥-11

This is always true so x can be and real number

{-infinity, infinity}

-2|5x+3| = 8

Divide by -2

-2/-2|5x+3| = 8/-2

|5x+3| = -4

This can never happen because absolute values are zero or greater

no solution

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Answer:

Equation that apply to the table:

y= 10x +2 and y= 2x +10

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What is the solution set of the following system of equations?
9966 [12]
5x - 3y = 10
x + y = 7......multiply by -5
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5x - 3y = 10
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x + y = 7
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3 years ago
2. A,B,C,D ? <br> 3. A,B,C,D ?
Tema [17]
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6 0
3 years ago
53​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the
faltersainse [42]

Answer:

a

   P(X = 5) = 0.2423

b

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c

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Step-by-step explanation:

From the question we are told that

   The population proportion is   p = 0.53

    The sample size is  n = 10

Generally the distribution of the confidence of US adults in newspapers follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators        

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is exactly​ five is mathematically represented as

     P(X = 5) =  ^{10}C_5 *  0.53^5 *  (1- 0.53)^{10-5}

=>  P(X = 5) =  252 * 0.04182 *  0.023

=>  P(X = 5) = 0.2423

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is  at least​ six is mathematically represented as

  P( X \ge  6 )=  P( X  = 6) +  P( X  = 7) +  P( X  = 8) +  P( X  = 9) +  P( X  = 10)

=> P( X \ge  6 )=  [^{10}C_6 *  [0.53]^6 *  (1- 0.53)^{10-6}] +  [^{10}C_7 *  [0.53]^7 *  (1- 0.53)^{10-7}] +  [^{10}C_8 *  [0.53]^8 *  (1- 0.53)^{10-8}] +  [^{10}C_9 *  [0.53]^9 *  (1- 0.53)^{10-9}] + [^{10}C_{10} *  [0.53]^{10} *  (1- 0.53)^{10-10}]

=> P( X \ge  6 )=  [0.227] +  [0.1464] +  [0.0619] +  [0.0155] + [0.00082]

=> P( X \ge  6 )=  0.4516

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is  less than four is mathematically represented as

    P( X <  4 )=  P( X  = 3) +  P( X  = 2) +  P( X  = 1) +  P( X  = 0)

=>  P( X <  4 )=  [^{10}C_3 *  0.53^3 *  (1- 0.53)^{10-3}] +  [^{10}C_2 *  0.53^2 *  (1- 0.53)^{10-2}] +  [^{10}C_1 *  0.53^1 *  (1- 0.53)^{10-1}] +  [^{10}C_0 *  0.53^0 *  (1- 0.53)^{10-0}]

=>  P( X <  4 )=  0.09051  +  0.03 +  0.0059 +  0.000526

=>  P( X <  4 )=  0.12694

5 0
3 years ago
How many solutions does the equation 2x-6=6+2x
Alex_Xolod [135]

Answer:

2 solutions

Step-by-step explanation:

Since the equations are not equal, they provide two solutions. Negative numbers provide no solutions. If they are equal to zero, they have one solution.


5 0
3 years ago
Read 2 more answers
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