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2 years ago

Midsegments DE= 7, EF=12 DF=16 if D, E, and F are midpoints of the sides of triangle ABC, find the perimeter of triangle of ABC

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

7 0

Answer:

In a triangle, the segment joining the midpoints of any two sides will be parallel to the third side and half its length ⇒DE is parallel to AC, and DE = 8, AC=16.

Similarly, DF is parallel to BC, and DF=6, BC=12

Step-by-step explanation:

Similarly, EF is parallel to AB, and EF=3.5, AB=7

Hence, perimeter of ΔDEF = 8+6+3.5 = 17.5

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1.32:3 1/7 =(1.4y): 5/6

alina1380 [7]

After solving $1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$ we get y=0.24

Step-by-step explanation:

We need to solve the ratio: $1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$ and find value of y

Solving:

$1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$

Converting fractions into decimals

$1.32:3.14=(1.4y):0.83$

Ratio can be written as:

$\frac{1.32}{3.14}=\frac{1.4y}{0.83}$

Now cross multiply

$1.32*0.83=1.4y*3.14$

$1.09=4.39y$

$y=\frac{1.09}{4.39}$

$y=0.24$

So, after solving $1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$ we get y=0.24

Keywords: Ratio

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Answer:

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