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2 years ago

PLEASE HELP ME! It’s easy I just don’t remember.

Mathematics

1 answer:

damaskus [11]2 years ago

6 0

Answer:

Solve the trigonometric equation by isolating the function and then taking the inverse. Use the period to find the full set of all solutions.

θ=arccot(x/o)

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The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. A wind speed of 37 miles per ho

vfiekz [6]

Answer:the output for a wind speed of 40 miles per hour is 810.8 kilowatts.

Step-by-step explanation:

The power P produced by a wind turbine is directly proportional to the cube of the wind speed S. This means that

P is directly proportional to S

Introducing a constant of proportionality, k, it becomes

P = kS

A wind speed of 37 miles per hour produces a power output of 750 kilowatts. This means that

750 = k × 37

k = 750/37 = 20.27

The expression becomes

P = 20.27S

Therefore, the output for a wind speed of 40 miles per hour would be

P = 20.27 × 40

P = 810.8

6 0

2 years ago

!!!!!! URGENT PLS HELP ME ANSWER !!!!

laila [671]

Answer:

1) A = 547.1136, C = 82.896

2) A = 678.5226, C = 92.316

3) A = 844.5344, C = 102.992

4) A = 1554.49625, C = 139.73

5) A = 1561.4906, C = 140.044

6) A = 994.8776, C = 111.784

Step-by-step explanation:

$A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{26.4}{2})^2 = 3.14 * 13.2^2 = 547.1136$

$C = \Pi D = 3.14 * 26.4 = 82.896$

$A = \Pi r^2 = 3.14*(14.7)^2 = 678.5226$

$C = 2\Pi r = 14.7*2 * 3.14 = 92.316$

$A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{32.8}{2})^2 = 3.14 * 16.4^2 = 844.5344$

$C = \Pi D = 3.14 * 32.8 = 102.992$

$A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{44.5}{2})^2 = 3.14 * 22.25^2 = 1554.49625$

$C = \Pi D = 44.5*3.14 = 139.73$

$A = \Pi r^2 = 3.14*22.3^2 = 1561.4906$

$C = 2\Pi r = 2 * 3.14 * 22.3 = 140.044$

$A = \Pi r^2 = 3.14 * 17.8^2 = 994.8776$

$C = 2\Pi r = 2 * 3.14 * 17.8 = 111.784$

8 0

2 years ago

Use the divergence theorem to find the outward flux of the vector field F(xyz)= 4x^2 i + 4y^2 j + 3z^2 k across the boundary of

Pavel [41]

$\vec F(x,y,z)=4x^2\,\vec\imath+4y^2\,\vec\jmath+3z^2\,\vec k\implies\nabla\cdot\vec F=8x+8y+6z$

Let $S$ be the surface of the rectangular prism bounded by the planes $x=0$ , $x=a$ , $y=0$ , $y=b$ , $z=0$ , and $z=c$ . By the divergence theorem, the integral of $\vec F$ over $S$ is given by the integral of $\nabla\cdot\vec F$ over the interior of $S$ (call it $R$ ):