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nataly862011 [7]
2 years ago
6

Calculate the highest common factor (HCF) for 64 ​

Mathematics
2 answers:
harkovskaia [24]2 years ago
7 0

Answer:

factors of 64= 1,2,4,8,16,32 and 64

Step-by-step explanation:

when you speak of HCF.

it should be when comparing 2 or more factors

lord [1]2 years ago
6 0

Answer:

1 2 4 8 16 32 64

Step-by-step explanation:

prime factors of 64 is 2 so

2____64

2____32

2____16

2_____8

2_____4

2_____2

1

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gavmur [86]
The first step is seeing how many times 5 can go in 48. 5 can go in 48 9 times. Then you multiply 310 by 9 which equals 2790. Then you divide 310 by 5 which equals 62. Then you add 62 , three times, to 2790. 
The final answer is 2979 quarts.
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The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction
Len [333]

Answer:

(a) <em>                             </em><em>n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.

Assuming that the random variable <em>X </em>follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

  • For a sample size of <em>n</em> = 20

P(\mu-200

                                           =P(-0.37

  • For a sample size of <em>n</em> = 50

P(\mu-200

                                           =P(-0.59

  • For a sample size of <em>n</em> = 100

P(\mu-200

                                           =P(-0.83

  • For a sample size of <em>n</em> = 500

P(\mu-200

                                           =P(-1.86

<em>                                  n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample (\bar x) approaches the whole population mean (\mu_{x}).

Consider the probabilities computed in part (a).

As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.

So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.

Thus, the correct option is (b).

8 0
3 years ago
Please help, will give extra points
asambeis [7]

Answer:

59 degrees

Step-by-step explanation:

Since angle BGC is 40 degrees and angle AGC is 19 degrees and they are asking for angle AGB which is the sum of both angles together, you just add the 40 degrees plus 19 degrees.

6 0
3 years ago
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