Question

Jared has a bag that contains 8 blue marbles, 6 red marbles, and 10 green marbles. He selects a marble, replaces it in the bag, and then selects another marble. What is the probability that both marbles are green?
A. 5/72
B. 10/144
C. 25/144
D. 5/6
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Answer 1

The answer is b. 10/144

Answer 2

Answer:

Option C.

Step-by-step explanation:

Jared has a bag that contains marbles of different colors.

Number of blue marbles = 8

Number of red marbles = 6

Number of green marbles = 10

Total marbles in the bag = 8 + 6 + 10 = 24 marbles

He selects a marble from the bag, replace it and then select  a marble again.

The probability that first marble would be green =  $\frac{10}{24}$

the probability that another marble would be green =  $\frac{10}{24}$

The probability that both marbles would be green

=  $\frac{10}{24}$ ×  $\frac{10}{24}$

=  $\frac{5}{12}$ ×  $\frac{5}{12}$

=  $\frac{25}{144}$

The answer would be Option C.  $\frac{25}{144}$