Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:

The probability of both failing the test and being unfit is:

Hence, the conditional probability is:

0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287
That equals <u>.0124031008</u>
Step-by-step explanation:
f'(x) = d/dx [f(x)]
= d/dx (sinx + e^x) = cosx + e^x.
Therefore f'(0) = cos(0) + e^(0) = 2.
Plotting the 4 points and doing visual inspection will tell us if the quadrilateral is a parallelogram. We can also do analytical techniques which are to determine the slope and the distance between the points. Doing either of these two will give us
<span>B. Yes,TUVW quadrilateral s a parallelogram because there are two pairs of parallel sides.
</span>
Answer:
c is it
Step-by-step explanation:
Rawr hope it helps