Can Anyone please solve this? Will mark brainiest!!!!
1 answer:
Answer:
(a) see attached
(b) CD = 29
Step-by-step explanation:
<h3>(a) </h3>See the attachment for a diagram.
In the diagram, we have shown point E on the plane so that BE is parallel to AC.
__
<h3>(b)</h3>Triangle BDE is a right triangle with hypotenuse BD = 25 and leg BE = AC = 15. The length DE is given by the Pythagorean theorem as ...
DE = √(BD^2 -BE^2) = √(625 -225) = 20
Triangle CDE is a right triangle with hypotenuse CD and legs CE = 21 and DE = 20. The length of the hypotenuse is also given by the Pythagorean theorem as ...
CD = √(CE^2 +DE^2) = √(21^2 +20^2) = √841
CD = 29
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Answer:
y=5
Step-by-step explanation:
We are solving
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Or what power should I raise 2 to so that it will give me 32?
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Therefore .
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We are given the equation:
..........(1)
Now we have to write it in quadratic form using substitution.
The general form of quadratic equation is given by:
So let us say
.......(2)
Plugging the value of (x-5)² from equation (2) in (1),
Answer : Option B.