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3 years ago

How does a security information and event management system (SIEM) in a SOC help the personnel fight against security threats

1 answer:

6 0

A security information and event management (SIEM) system in an SOC helps fight security threats by combining data from varying technology sources and analyzing logs in real time, which helps in managing resources to implement protective measures against threats.

<h3 /><h3>Features of a SIEM</h3>

They are tools used to promote information security through the provision of reports that display malicious intrusion attempts and alerts that are triggered in case of violation of established rules for security.

Therefore, through SIEM tools there is greater analysis and collection of data that can impact information security, generating a better classification of threats and investigative capacity to carry out actions to combat system insecurities.

Find out more information about security information here:

brainly.com/question/26282951

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Which of the following demonstrates the proper way to specify a variable-length argument list?

larisa86 [58]

Answer:

The answer to this question is option "d".

Explanation:

In the given question option d is correct because variable-length argument is a new feature in J2SE 5.0 which stands for java 2 standard edition and 5.0 is the version name. It is the variable-length argument lists. A coder can create functions that uses a function to receive several parameter that is not specified. An argument type followed by an ellipsis(...) in the parameter list of a method means that a fixed number of arguments of that particular type is obtained by the method. and other options are not correct that can be given as:

In option a, we do not need to use the string the variable-length argument list. That's why it is wrong.
The option b and c are all wrong because in the last parameter the variable-length argument list is used.

That's why the answer to this question is the option "d".

7 0

3 years ago

Consider the following sequence, defined from n=2 to 15 (inclusive). Pn=n2−1. Produce a list named primes which only contains va

omeli [17]

Answer:

primes = []

for n in range(2,16):

pn = n*n - 1

if is_prime(pn):

primes.append(pn)

5 0

3 years ago

What does a spam e-mail normally promise you?

nlexa [21]

The answer is a virus

7 0

3 years ago

CHALLENGE ACTIVITY |

fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

double maxVal = 0.0;

if (num1 > num2) { // if num1 is greater than num2,

maxVal = num1; // then num1 is the maxVal. }

else {

maxVal = num2; // num2 is the maxVal. }

return maxVal; }

int main() {

double numA;

double numB;

double numY;

double numZ;

double maxSum = 0.0;

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

cout << "maxSum is: " << maxSum << endl; }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0 as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0

3 years ago

// This pseudocode segment is intended to compute and display

Finger [1]

The pseudocode to calculate the average of the test scores until the user enters a negative input serves as a prototype of the actual program

<h3>The errors in the pseudocode</h3>

The errors in the pseudocode include:

Inclusion of unusable segments
Incorrect variables
Incorrect loops

<h3>The correct pseudocode</h3>

The correct pseudocode where all errors are corrected and the unusable segments are removed is as follows:

start

Declarations

num test1

num test2

num test3

num average

output "Enter score for test 1 or a negative number to quit"

input test1

while test1 >= 0

output "Enter score for test 2"

input test2

output "Enter score for test 3"

input test3

average = (test1 + test2 + test3) / 3

output "Average is ", average

output "Enter score for test 1 or a negative number to quit"

input test1

endwhile

output "End of program"

stop