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Which statement about synchronous communication is true?

tangare [24]

In general, synchronous communication means you have to wait for the answer all the time. The programming logic is simpler, but the cost that you spend a lot of time waiting.

If the options are:

<span>a. The people communicating don't need to be online at the same time.
b. There is lag time in the communication.
c. The communication occurs in real time.

a is false, you do need to be online to receive the message
b is true, typically you continue only after an acknowledgement
c is true, you wait for acknowledgement that occurs in real time (not necessarily fast though)</span>

3 0

3 years ago

What is spread sheet software?

melamori03 [73]

Answer:

The answer to this question is given in the explanation section.

Explanation:

This is a type of software which show us data in tabular form. These software can easily store, analyze and organize data.

They are divided in rows and columns. They are mainly used for accounting and book keeping.

The commonly used spread sheet software in the market are MS Excel by Microsoft, Calc by libre office.

3 0

3 years ago

Write two cin statements to get input values into birthMonth and birthYear. Then write a statement to output the month, a dash,

snow_lady [41]

Answer:

// here is code in c++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

// variables to read birth month and year

int birthMonth,birthYear;

cout<<"Enter the birth month:";

// read the birth month

cin>>birthMonth;

cout<<"Enter the birth Year:";

// read the birth year

cin>>birthYear;

// print the output

cout<<birthMonth<<"-"<<birthYear<<endl;

return 0;

}

Explanation:

Declare two variables "birthMonth" and "birthYear". Read the value of birthMonth and birthYear from user. Then print the birth month and birth year and a dash(-) in between them.

Output:

Enter the birth month:1

Enter the birth Year:2000

1-2000

Enter the birth month:5

Enter the birth Year:1950

5-1950

6 0

2 years ago

Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur

sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

for ip in range(octet_start, octet_end):

forth_octet = forth_octet + 1

if forth_octet > 255:

forth_octet = (forth_octet % 255) - 1

third_octet = third_octet + 1

if third_octet > 255:

third_octet = (third_octet % 255) - 1

second_octet = second_octet + 1

if second_octet > 255:

second_octet = (second_octet % 255) - 1

first_octet = first_octet + 1

if first_octet > 255:

print("No more available IP!")

break

print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0

3 years ago

In this lab, you declare and initialize variables in a C++ program. The program, which is saved in a file named NewAge.cpp, calc

Ne4ueva [31]

Answer:

#include <iostream>

using namespace std;

int main() {

int currentYear = 2020;

int myCurrentAge = 23;

int myNewAge=myCurrentAge+(2050-currentYear);

cout << "My Current Age is " << myCurrentAge << endl;

cout << "I will be " << myNewAge << " in 2050." << endl;

}

Explanation:

Initialize the currentYear with 2020 and myCurrentAge with 23.
Add myCurrentAge with the the result of (2015 - currentYear) and assign this result to myNewAge variable.
Finally display my current age and after that display the new age in 2050.

Output:

My Current Age is 23

I will be 53 in 2050.

6 0

3 years ago