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Afina-wow [57]
2 years ago
6

Blood contains three types of cells including red blood​ cells, white blood​ cells, and platelets. For approximately every 510 r

ed blood cells in humans with certain medical​ conditions, there are 30 platelets and 3 white blood . Write the ratio of red blood cells to platelet cells.
Mathematics
1 answer:
Aleks04 [339]2 years ago
6 0

Answer:

I believe your answer would be \frac{1}{17}

Step-by-step explanation:

Take 510, divide it by 30.

510/30 = 17

This means, every 17 red blood cells, there is 1 platelet, or  \frac{1}{17}

Hope this helps! - Zac

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Answer:

C. 12

Step-by-step explanation:


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2 years ago
Andy is solving a quadratic equation using completing the square. If a step in the process results in = (x – 6)2, could the orig
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7 0
2 years ago
Read 2 more answers
What is the cost of each item? What is the subtotal? What is the tax? What is the total paid? Shoes: $49.99 (normally) they are
prisoha [69]

Answer:

Cost of shoes = $37.4925

Cost of jacket = $92.4533

Tax = $9.81

Total paid = $144.2458

Step-by-step explanation:

Normal price of shoes = $49.99

Discount = 25%

Discounted price:

\$49.99 - \$49.99\times \dfrac{25}{100} = \$37.4925

Normal price of jacket = $137.99

Discount = 33%

Discounted price:

\$137.99 - \$137.99\times \dfrac{33}{100} = \$92.4533

Price of pack of cookies = $4.49

No discount on cookies as per question statement.

Total amount without tax = $37.4925 + $92.4533 + $4.49 = $134.4358

Sales Tax = 7.3% of total amount without tax = 7.3% \times $134.4358 = $9.81

Total paid = $134.4358 + $9.81 = <em>$144.2458</em>

4 0
2 years ago
let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
2 years ago
A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s
Artemon [7]

Answer:

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age  \leq 3}\end{array}\right

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 0 \  \leq  age   \leq  2 }\\{0 \  \leq  age   \leq 3}\end{array}\right]

Also , the age transition matrix is as follows:

L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]

After 1 year ; the age distribution vector will be :

x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]  \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq 1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age   \leq  3}\end{array}\right

6 0
2 years ago
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