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3 years ago

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There are six poles on a side of a 1 km 200 m long straight road such that there is a pole at the starting and end points of the

road. If the poles are equally spaced, then what is the distance between each consecutive pole?

1 answer:

Bingel [31]3 years ago

5 0

Answer:

Distance is 200m between each pole

Step-by-step explanation:

First, convert the length of the road into meters

1km= 1000m

1000m +200m= 1200m

There are 6 poles on the side and they're equally spaced

Divide the length of the road by the number of poles to get the distance between the poles

Distance between poles= Length of road/ Number of poles

Distance between poles= 1200m/ 6 poles

Distance between poles= 200m

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AURORKA [14]

Answer:

1/16 of a mile left to walk to reach the end of the road

Step-by-step explanation:

The total distance to be walked = 15/16 miles

already walked= 7/8 miles = 14/16 miles

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The Length of a rectangle exceeds its breadth by 9 cm. if length and breadth are each increased by 3 cm, the area of new rectang

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Answer:

Breadth = 8 cm

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Step-by-step explanation:

Given rectangle:

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x² + 15x + 36 = 84 + x² + 9x

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6x - 48 = 0

6x = 48

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3 years ago

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Answer:

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2 years ago

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3 years ago

Read 2 more answers

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

5 0

2 years ago