If an angle of a parallelogram is two-third of its adjacent angle, then the smallest angle of the parallelogram is 72°. Adjacent angles exhibit a common side and a corner point.
Adjacent angles exhibit a common side and a corner point, although they do not overlap.
A parallelogram can be defined as a simple type of quadrilateral having two pairs of parallel sides.
A rectangle can in turn be defined as a parallelogram having four right angles (90°), thereby all rectangles represent quadrilaterals.
The sum of the adjacent angles of a parallelogram is equal to 180°.
In this case, we have that the sum of adjacent angles >> X + 2/3 X = 180° >> X = 108° >> 2/3 X = 72°
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The numbers at which <em>f</em> is not differentiable are;<u> -1, and 2</u>
The reason the above list of numbers at which <em>f</em> is not differentiable are correct are given as follows:
<em>Question; Please find attached a graph that can be used to solve the question</em>
- A function is not differentiable at a point where the function has a discontinuity. That is a point on the graph were there is a break in the graph
Therefore, the given graph of <em>f</em> shows that <u>the function is not differentiable at x = -1</u>, the point where the graph has a discontinuity
- A function is not differentiable at a point where the graph of the function has a kink or corner.
The graph of <em>f</em> has a kink at x = 2, therefore, <u>the function is also not differentiable at x = 2</u>
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Difference between the mean of the data, including the outlier and excluding the outlier is;
B: 0.93
<h3>Mean average</h3>
Her time in minutes for the given months are;
- January = 41.55 minutes
- July = 36. 38 minutes
- Feb = 42.51 minutes
- Aug = 38.48 minutes
- Mar = 43. 01 minutes
- Sept = 41.87 minutes
- Apr = 39. 76 minutes
- Oct = 51.32 minutes
- May = 37. 32 minutes
- Nov = 42.59 minutes
- June = 35.28 minutes
- Dec = 43.71 minutes
Looking at all the numbers, they largely range from 36 to 44 which means that the outlier is 51.32
Total number of minutes with outlier = 493.78 minutes
Number of months = 12
Thus;
Mean with outlier = 493.78/12
Mean with outlier = 41.15 minutes
Mean without outlier = (493.78 - 51.32)/(12 - 1)
Mean without outlier = 40.22 minutes
Thus;
Difference in both means = 41.15 - 40.22
Difference = 0.93
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Answer:
a. 99.30% of the woman meet the height requirement
b. If all women are eligible except the shortest 1% and the tallest 2%, then height should be between 58.32 and 68.83
Explanation:
<em>According to the survey</em>, women's heights are normally distributed with mean 63.9 and standard deviation 2.4
a)
A branch of the military requires women's heights to be between 58 in and 80 in. We need to find the probabilities that heights fall between 58 in and 80 in in this distribution. We need to find z-scores of the values 58 in and 80 in. Z-score shows how many standard deviations far are the values from the mean. Therefore they subtracted from the mean and divided by the standard deviation:
z-score of 58 in=
= -2.458
z-score of 80 in=
= 6.708
In normal distribution 99.3% of the values have higher z-score than -2.458
0% of the values have higher z-score than 6.708. Therefore 99.3% of the woman meet the height requirement.
b)
To find the height requirement so that all women are eligible except the shortest 1% and the tallest 2%, we need to find the boundary z-score of the
shortest 1% and the tallest 2%. Thus, upper bound for z-score has to be 2.054 and lower bound is -2.326
Corresponding heights (H) can be found using the formula
and
Thus lower bound for height is 58.32 and
Upper bound for height is 68.83