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3 years ago

HELP

Mathematics

1 answer:

Nonamiya [84]3 years ago

6 0

Answer:

Here are some expressions you could use!

15j + 15

5(2j + 3 + j)

25(10j + 18 + 5j)

4(5j + 8 + 4j)

10(4j + 6 + 2j)

All of these are right you can choose which one to use! 25(10j + 18 + 5j) is the easiest one to solve in my opinion.

Step-by-step explanation:

qaesrxdgjk

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What is the value of p?

Misha Larkins [42]

P=pie which could be 8

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3 years ago

One lap around the track is 400 meters. If Sean ran around the track 5 and 1/2 times, how far did Sean run?

telo118 [61]

2200 meters...I think

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3 years ago

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Jon has 6 kites he and his friends will each fly one kite how many people in all will fly a kit

True [87]

Answer:

Step-by-step explanation:

One person will fly a kite for each of the 6 kites Jon has.

6 people in all will fly a kite.

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3 years ago

2x - 3y = 45 and x + y = 10 what is the x - value of the solution of the system

abruzzese [7]

Answer:

x=15

Step-by-step explanation:

This is a simultaneous equation

2x-3y=45 ------------------------------ equation i

x+y=10 -------------------------------equation ii

from equation ii

x+y=10

make x the subject of the matter

we have,

x=10-y

in equation i

substitute x for 10-y

2x-3y=45----------------------i

since x=10-y

we have,

2(10-y) - 3y=45

20-2y=3y=45

collect like terms

-2y-3y=45-20

-5y=25

divide both sides by -5

we have y=-5

substitute y for-5 in equation i

x+y=10

x+-5=10

collect like terms

x=10+5

x=15

therefore

x=15

8 0

3 years ago

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Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio

s344n2d4d5 [400]

Answer:

A) $\frac{1}{1024},\frac{1}{4096}$

B) $\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) $\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

Step-by-step explanation:

1) Incomplete question. So completing the several terms: $\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}$

We can realize this a Geometric sequence, with the ratio equal to:

$q=\frac{1}{4}$

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

$\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}$

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

$\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) The explicit formula, is one valid for any value since we have the first one to find any term of the Geometric Sequence, therefore:

$\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

6 0

3 years ago