Answer:
90°
Step-by-step explanation:
Angle C = arccos((84²+13²-85²)/(2×84×13))
= arccos(0/2184)
= arccos(0)
= 90°
Answered by GAUTHMATH
Answer:
Step-by-step explanation:
Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:
Float on water: d < 0.0361 lb/in³ (where d denotes denisity)
Do not float on water: d > 0.0361 lb/in³
The answer is A! hope this helps! please brainliest!
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation: