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Kaylis [27]
2 years ago
13

Which of the following number lines represents the solution to -5 m = 10?

Mathematics
2 answers:
Lubov Fominskaja [6]2 years ago
7 0

Answer:

-2

Step-by-step explanation:

10/-5= -2

Negative times a negative equals to a positive: -2 x -5 = 10

sammy [17]2 years ago
3 0

Answer:

m=-2 I just had a test on this

Step-by-step explanation:

Divide each term by-5 and simplify

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Write an equation. <br><br>Four more than the product of three and a value x is equal to ninteen​
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Answer:

see explanation

Step-by-step explanation:

The product of 3 and x is 3x

Four more than this product is 3x + 4, thus

3x + 4 = 19 ← is the equation

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Refer to the diagram shown.
lions [1.4K]

Answer:

x=5

Step-by-step explanation:

According to SSS, RPS and RPQ should be similar angles. Since the length RP is the same, then RQP and RSP should be similar too. Therefore PRS and PRQ should be similar too. Since QP and RS are the same (7) then QR and PS needs to be same in length too.

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Math help please right now!!!!
Karolina [17]

Answer:

The second answer is correct.

Step-by-step explanation:

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1 year ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
3 years ago
David, Morris, and Jose are the stars of the schools’ basketball team. In the last game, David earned twice as many points as Mo
Alexus [3.1K]

Answer:

Since he earned one third as many as Jose

it's 8

Step-by-step explanation:

  • \frac{1}{3}  \times 24 = 8
3 0
3 years ago
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