She will need 9 computers. She has 8 groups of 3 and 1 group of 2. Therefore, she will need 9.
X is between -6 and 11 and y between -6 and 8
Answer:
So your question was not very clear but with (f+g) im guessing thats f(x)+g(x)
So first we add them x^2+4x-32 + x-4 then we will get x^2 + 5x - 36
Then we need to multiply both
(x^2+5x-36)(x^2+5x-36)
=
(x^2+5x-36)^2
The only reason im not solving it out is because it yields large numbers and you might not understand.
the answer is 4.565 JF$OFB#$UF
