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Zinaida [17]
2 years ago
15

Solve for c. 4(3+ c) +c=c+4

Mathematics
2 answers:
Alika [10]2 years ago
6 0
12+5c=c+4

4c=-8
C=-2

Please brainiest and like
vivado [14]2 years ago
4 0

Step-by-step explanation:

4(3 + c) + c = c + 4 \\ 12 + 4c + c = c + 4 \\ 12 + 5c = c + 4 \\ 12 + 4c = 4 \\ 4c = 4 - 12 \\ 4c =  - 8 \\ c =  - 2

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If p(x) = X squared -1 and q(x) = 5(x-1), which expression is equivalent to (p-q)(x)
hram777 [196]
Minus the functions
(p-q)(x)=p(x)-q(x)
p(x)=x^2-1
q(x)=5(x-1)

p(x)-q(x)=x^2-1-5(x-1)
p(x)-q(x)=x^2-1-5x+5
p(x)-q(x)=x^2-5x+4
(p-q)(x)=x^2-5x+4
or factored
(p-q)(x)=(x-4)(x-1)

8 0
3 years ago
Larisa earns $7 per hour.she worked 40 hours at the regular rate, 3 hours at time and half, and 6 hours at double time.
VARVARA [1.3K]

Answer:

$6.07/hr. if I understand the question properly.  See below.

Step-by-step explanation:

I don't see the question, but will assume we want to find Larisa's base pay.  The $7/hr given is the average for the work sequence noted in the problem.  If this is incorrect, ignore the answer.

==================================

Let x be Larisa's base salary.  We are told, I think, that in one stretch of time Larisa earned an average of $7/hour.  That was composed of:

<u>Hours</u>  <u>Rate($/hr)</u>

  40           x

    3        1.5x

<u>     6    </u>     2x

  49

Her total income over this period would be:

40x +3(1.5x) + 6(2x)  [The hours worked times the pay rate for each period]

Her average income per hour would be:

(40x +3(1.5x) + 6(2x))/49

which we are told is $7/hr.

(40x +3(1.5x) + 6(2x))/49 = 7

40x + 4.5x + 12x = 343

56.5x = 343

x = $6.07/hr

6 0
2 years ago
The equation d = 3t gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.
Natasha_Volkova [10]

Answer:

Liam's rate = 3 meters per second

Edgar's rate = 3.2 meters per second

Edgar swims faster

Step-by-step explanation:

<u>Liam:</u>

The equation d=3t gives the distance, d, in meters that Liam swims with respect to time, t, in seconds.

When t=0,\ d=0.

When t=1,\ d=3.

Rate of change:

\dfrac{3-0}{1-0}=3

Liam's rate is 3 metres per second.

<u>Edgar:</u>

When t=20, \ d=64.

When t=40,\ t=128.

Rate of change:

\dfrac{128-64}{40-20}=\dfrac{64}{20}=3.2

Edgar's rate is 3.2 metres per second.

Edgar swims faster.

5 0
3 years ago
Multiply 3 by 7 then subtract q from the result
Luda [366]

Answer:

21 - q

Step-by-step explanation:

3 * 7 = 21

21 - q = 21 - q

7 0
4 years ago
What is 8d=48 in algebra 1
Maru [420]
D=6
8d=48
8*d=48
d=48/8
d=6
8(6)=48
48=48
6 0
3 years ago
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