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Goshia [24]
2 years ago
12

What is the distance between the points (−7, 1) and (−7, −5) on the coordinate plane?

Mathematics
1 answer:
4vir4ik [10]2 years ago
6 0

Answer:

\displaystyle d = 6

General Formulas and Concepts:
<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Coordinate Planes

  • Coordinates (x, y)

<u>Algebra II</u>

Distance Formula: \displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

Point (-7, 1)

Point (-7, -5)

<u>Step 2: Find distance </u><u><em>d</em></u>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>.

  1. Substitute in points [Distance Formula]:                                                     \displaystyle d = \sqrt{(-7 - -7)^2 + (-5 - 1)^2}
  2. [Order of Operations] Evaluate:                                                                  \displaystyle d = 6
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1: 8

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4 : 32

Divide both the left and right side by 4

4/4 =1

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4:32  becomes  1:8

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Answer:

The interval is (.0817, .118).

Step-by-step explanation:

Let's make this interval! The easy way is to go to STAT->TEST->A, 1-prop z-int, but I will show the long way.

<u>1. Conditions</u>

First we must check the conditions.

<em>Randomization condition: </em>The sample is given to be random, so we can assume independence.

<em>Success/failure condition: </em>Both np>10 and nq>10 must be met.

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  • nq = 1030(927/1030) = 927 ✓

<em>10% condition: </em>The sample cannot be greater than 10% of the population.

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All conditions are met, so we can use <u>a 1-proportion z-interval</u> to represent the data.

<u></u>

<u>2. Mechanics</u>

<u>Find </u>\hat{p}<u>, the sample proportion.</u>

103/1030 = .1

\hat{q}, then, the probability of not p, is 1 - .1 = .9

<u>Find z* (z star), the critical z-value.</u>

You can do this on your calculator using 2nd->VARS->3 (or you can memorize it - it's 1.96. Winky face.) This is called the invNorm function, that takes the left side area under the normal curve. But what do we plug in to the invNorm function?

invNorm(.975) = 1.96

<u>Plug values into the equation.</u>

\hat{p} ± z*\sqrt{\frac{\hat{p}\hat{q}}{n} }

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.1 - .0183 = .0817

.1 + .0183 = .118

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<u>3. Conclusion</u>

Based on this sample, we are 95% confident that the proportion of people the company contacts who may buy something is between .0817 and .118. That isn't very likely, but maybe they'll make a little profit!

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