I think it’s condensation of steam
Answer:
I just learned this topic and have the same question, so I'm not sure if this right. However, I see a fellow student struggling and have to at least put in what I know. My equation was f(n) = 64(1/2)^n-1, then the question was write an expression to represent f(20).
Step-by-step explanation:
So, my answer was f(20) = 64(1/2)^19
f(20) is the number you plug into n. And because the exponent is n-1, I knew to subtract 1 from 20 to get 19.
Then I just wrote the equation out like the original expect with the numbers pluged in: f(20) = 64(1/2)^19
I hope this helps!
Its B because if you do the relationship right then your answer will be B
Type o ( ii) = 6 . 25
Type A ( l^A l ^A or l ^A i ) = 18 . 75
Type B ( l ^b l^b or l ^ bi ) = 18.75
Type AB ( l ^ A l^ B) = 56.25
If you're just starting calculus, perhaps you're asking about using the definition of the derivative to differentiate
.
We have

Expand the numerator using the binomial theorem, then simplify and compute the limit.

In general, the derivative of a power function
is
. (This is the aptly-named "power rule" for differentiation.)