Solve the following:

If you buy something at a 20% discount off the listed price of $ 97, but pay a sales tax of 10% after the discount is applied, h

kaheart [24]

$85.36 is the correct answer

8 0

3 years ago

Pls help brainlist pls help

Len [333]

Answer:

1. V = 157in³, so the volume of the sugar container is 157in³

2. h = 12in, so the height of the rice container is 12in

3. The rice container's height is 12in and the height of the sugar container is 8in, which means the rice container is taller by 4in. The rice container's volume is 235.5in and the sugar container's volume is 157in, so the rice container's volume is greater than the volume of the sugar container's volume by 78.5in.

4. V = 50.24in³, so the volume of the flour container is 50.24in³

5. The rice container's volume is 235.5in, the sugar container's volume is 157in, and the flour container's volume is 50.24in. This means the container that contains the greatest volume is the rice container and the container that contains the smallest volume is the flour container.

Step-by-step explanation:

1. to find the volume of a cylinder, we use the formula:

V = πr²h

V = 3.14(2.5² × 8)

V = 3.14(6.25 × 8)

V = 3.14(50)

V = 157in³

2. To find the height of a cylinder when given the volume and radius, you use the formula:

h = V / πr²

h = 235.5/3.14(2.5²)

h = 235.5/3.14(6.25)

h = 235.5/19.625

h = 12in

h = height

3. The rice container's height is 12in and the height of the sugar container is 8in, which means the rice container is taller by 4in. The rice container's volume is 235.5in and the sugar container's volume is 157in, so the rice container's volume is greater than the volume of the sugar container's volume by 78.5in.

4.

V = bh

V = 12.56 × 4

V = 50.24in³

5. The rice container's volume is 235.5in, the sugar container's volume is 157in, and the flour container's volume is 50.24in. This means the container that contains the greatest volume is the rice container and the container that contains the smallest volume is the flour container.

5 0

2 years ago

10 ft

Maru [420]

Answer: hi

Step-by-step explanation:

need points use photo math

on phone

5 0

3 years ago

How do you turn 90 + 2 as a numeral

LuckyWell [14K]

Can the sides of a triangle have lengths 8, 11, and 17? yes no Submit

3 0

3 years ago

Read 2 more answers

Please help with this calculus problem!

ELEN [110]

$\dfrac{\mathrm dQ}{\mathrm dt}=\dfrac{a(1-5bt^2)}{(1+bt^2)^4}$
$Q(t)=\displaystyle\int\frac{a(1-5bt^2)}{(1+bt^2)^4}\,\mathrm dt$

Let $t=\dfrac1{\sqrt b}\tan u$ , so that $\mathrm dt=\dfrac1{\sqrt b}\sec^2u\,\mathrm du$ . Then the integral becomes

$\displaystyle\frac a{\sqrt b}\int\frac{1-5b\left(\frac1{\sqrt b}\tan u\right)^2}{\left(1+b\left(\frac1{\sqrtb}\tan u\right)^2\right)^4}\sec^2u\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int\frac{1-5\tan^2u}{(1+\tan^2u)^4}\sec^2u\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int\frac{1-5\tan^2u}{\sec^6u}\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int(\cos^6u-5\sin^2u\cos^4u)\,\mathrm du$
$=\displaystyle\frac a{\sqrt b}\int(6\cos^2u-5)\cos^4u\,\mathrm du$

One way to proceed from here is to use the power reduction formula for cosine:

$\cos^{2n}x=\left(\dfrac{1+\cos2x}2\right)^n$

You'll end up with

$=\displaystyle\frac a{16\sqrt b}\int(5\cos2u+8\cos4u+3\cos6u)\,\mathrm du$
$=\displaystyle\frac a{16\sqrt b}\left(\frac52\sin2u+2\sin4u+\frac12\sin6u\right)+C$
$=\dfrac a{32\sqrt b}(5\sin2u+4\sin4u+\sin6u)+C$
$Q(t)=\dfrac{at}{(1+bt^2)^3}+C$

6 0

3 years ago

Solve the following:​

Solve the following: