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Alenkasestr [34]
2 years ago
5

SimplifySquare root of 50 over 2 times -4 + square root of 121

Mathematics
1 answer:
kobusy [5.1K]2 years ago
4 0

Answer:

  -9

Step-by-step explanation:

  \sqrt{\dfrac{50}{2}}\cdot(-4)+\sqrt{121}=-4\sqrt{25}+11=-4\cdot5+11\\\\=-20+11=\boxed{-9}

Your calculator can help with this.

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1+1+1+1+1+1+1+1+1+1 who would like to be my friend 1+1+1+1+1+1+1+1
ycow [4]

Answer:

i would :)))))

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
a jogger run 3 miles north and 5.5 miles east . what is the shortest distance back to their starting point
r-ruslan [8.4K]
You subtract 3 miles from the 5.5 miles which gives you  2.5

6 0
3 years ago
Item 18 you and your friend are selling tickets to a charity event. you sell 7 adult tickets and 16 student tickets for $120. yo
quester [9]

Answer:

  $4

Step-by-step explanation:

The two purchases can be written in terms of the cost of an adult ticket (a) and the cost of a student ticket (s):

  7a +16s = 120 . . . . . . . . price for the first purchase

  13a +9s = 140 . . . . . . . . price for the second purchase

Using Cramer's rule, the value of s can be found as ...

  s = (120·13 -140·7)/(16·13 -9·7) = 580/145 = 4

The cost of a student ticket is $4.

_____

<em>Comment on Cramer's Rule</em>

Cramer's rule is particularly useful for systems that don't have "nice" numbers that would make substitution or elimination easy methods to use. If you locate the numbers in the equation, you can see the X-patterns that are used to compute the numerator and denominator differences.

The value of a is (16·140 -9·120)/(same denominator) = 1160/145 = 8. I wanted to show you these numbers so you could see the numerator X-pattern for the first variable.

__

Of course, graphical methods can be quick and easy, too.

8 0
3 years ago
Charles has a collection of dimes and quarters worth $1.25. He has 8 coins. Write a systems of equations to represent this situa
Dima020 [189]

Answer:

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

Charles has 5 dimes and 3 quarters

Step-by-step explanation:

* Lets explain how to solve the problem

- Charles has a collection of dimes and quarters worth $1.25

- He has 8 coins

* To solve the problem remember that:

# 1 dim = 10 cents

# 1 quarter = 25 cents

# 1 dollar = 100 cents

- Assume that the number of dimes is d and the number of

 quarter is q

∵ Charles has 8 coins

- The number of dimes and the number of quarters equal the

  number of the coins

∴ d + q = 8 ⇒ (1)

∵ 1 dime = 10 cents

∴ The value of dimes = 10 × d = 10d

∵ 1 quarter = 25 cents

∴ The value of quarters = 25 × q = 25q

∵ The collection worth $1.25

∵ 1 dollar = 100 cents

∴ The collection worth = 1.25 × 100 = 125 cents

∴ 10d + 25q = 125 ⇒ (2)

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

* Lets solve the equations

- Multiply equation (1) by (-10) to eliminate d

∴ -10d + -10q = -80 ⇒ (3)

- Add equations (2) and (3)

∴ 15q = 45

- Divide both sides by 15

∴ q = 3

- Substitute the value of q in equation (1) to find the value of d

∴ d + 3 = 8

- Subtract 3 from both sides

∴ d = 5

∵ d represents the number of dimes and q represents the number

  of quarters

∴ Charles has 5 dimes and 3 quarters

4 0
4 years ago
A right triangle is _______ an equilateral triangle <br><br> A. Never<br> B. Sometimes<br> C. Always
hjlf

A . Never equilateral

5 0
3 years ago
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