1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex17521 [72]
2 years ago
14

Solve for the solution of the following system

Mathematics
1 answer:
NARA [144]2 years ago
4 0

Answer:

A

Step-by-step explanation:

To solve using the substitution method let's try to isolate the y variable in the first given equation: 2x + y = 6

Subtract 2x from both sides

2x + y = 6

- 2x       - 2x

y = 6 - 2x

Now plug the new y into the second equation: 3y - 18 = -6x

3(6 - 2x) - 18 = -6x

18 - 6x - 18 = -6x

-6x = -6x

Since we get that both sides of the equation are exactly the same, that means the solution can be all real numbers.

You might be interested in
Solve for p.<br><br> 4p + 19 + 13p = –17 − p
Marina CMI [18]

Answer:

p=-2

Step-by-step explanation:

4p + 19 + 13p = –17 − p

4p+13p=17p

17p + 19 = -17 - p

18p=-36

p=-2

7 0
3 years ago
Read 2 more answers
I’m confused on this one
andrew-mc [135]

First we need to know the point slope form. It is y - y1 = m(x - x1). In the y1 and x1 spots, you just plug in any coordinate on the line.

m would be the slope which we already know as 5/3.

We are given the coordinate point (0,3) as a point on the line. This is also what we are going to plug into the equation. 0 will be x1 and 3 will be y1.

Our equation should then look like after plugged in as....

y - 3 = 5/3(x)

x is by itself because subtracting or adding by 0 yield the original number.

6 0
3 years ago
What is the solution set of the equation<br> 3X=-6/1-X<br> for x # 1?
Irina-Kira [14]

The solution set of the equation 3X=-6/1-X for x # 1 is {-2,1)

3x = -6/(1-x)

3x(1-x) = -6

3x – 3x2 = -6

Taking 3 as common from both sides

x –x2 = -2

x2 – x +2 =0

Using factorisation method we will get two factors

Factoring quadratics is a method of expressing the quadratic equation ax2 + bx + c = 0 as a product of its linear factors as (x - k)(x - h), where h, k are the roots of the quadratic equation ax2 + bx + c = 0. This method is also is called the method of factorization of quadratic equations. Factorization of quadratic equations can be done using different methods such as splitting the middle term, using the quadratic formula, completing the squares, etc.

( x – 2)(x+1)=0

So, x = 2 , -1

Now, when x ≠ 1

The solution of the equation will vary from {-2,1) .

Learn more about the factorisation here brainly.com/question/13496719

#SPJ9

3 0
2 years ago
there are 10 tickets in each strip of carnival tickets. A total of 3850 tickets were sold in one day. how many strip of tickets
shusha [124]
385 ticket strips were sold
6 0
3 years ago
The first three terms of a sequence are
aliina [53]

Answer: 768

Step-by-step explanation:

3, 6 ,12 ,24, 48, 96, 192, 384, 768

12 x 2 = 48

48 x 2 = 96

96 x 2 = 192

192 x 2 = 384

384 x 2 = <u>768</u>

8 0
2 years ago
Other questions:
  • Felipe and Ling were asked to find an explicit formula for the sequence 24,16,8,0,...
    14·1 answer
  • I don't know how to solve this
    6·1 answer
  • he running track behind the local gym is 3/4 mile long. The track and field team ran 2 and 2/3 of a laps around the track. How m
    14·2 answers
  • In x-5=9, the correct way to isolate the variable is to
    10·1 answer
  • I need help to solve this question pls
    10·1 answer
  • What is the volume, in cubic centimeters, of a rectangular prism with a height of 8
    7·1 answer
  • Evaluate the radical expression. Express your answer in simplified form. If the expression does not represent a real number, ind
    11·2 answers
  • Use a single digit times a power of 10 to estimate the number 0.00002149 <br> please help :(
    11·1 answer
  • Identify the terms in the following:<br><br> a^2 + 2 +7b <br><br> Answer:
    8·1 answer
  • 4/3 divided by 5/4 in simplest form
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!