Complete question :
A 12-foot by 15-foot patio is increased by placing a stone border around the patio. The width of the border is the same all around the patio.The perimeter of the patio after it is expanded is 74 feet. The equation which represents x, the width of the border is 2[(12+2x)+15+2x)]=74. What is the width of the border?
1) 2 1/2 feet
2) 3 feet
4) 5 feet
5) 8 1/2 feet
Answer:
2.5
Step-by-step explanation:
Solving for X in the perimeter equation :
2[(12+2x)+15+2x)]=74
Open the bracket 
2[(12 + 2x + 15 + 2x)] = 74
2(27 + 4x) = 74
54 + 8x = 74
8x = 74 - 54
8x = 20
x = 20/8
x = 2.5
Hence, width fo border = 2.5
 
        
             
        
        
        
If the base is square, and the perimeter is 14.5, that means that each side of the base is 14.5/4=3.625. Since we now know the length and the width, as well as the height which is 16.8, we plug into the formula  . So, plug in the details
. So, plug in the details  Your answer will be 73.6 cm^3
 Your answer will be 73.6 cm^3
 
        
                    
             
        
        
        
Answer:
101 is your answer
Step-by-step explanation:
Remember to follow PEMDAS & the left->right rule.  
First, multiply 12 with 13:
12 x 13 = 156
Next, divide 156 with 2
156/2 = 78
Finally, add 23
78 + 23 = 101
101 is your answer
~
 
        
                    
             
        
        
        
28 BECAUSE IT CONTINUES THE PATTERN OF SUBTRACTING 4 FROMTHE AMOUNT PULLED PER GRADE
        
             
        
        
        
Answer:
   23.  0.4583 seconds
   24.  0.0107 seconds
Step-by-step explanation:
The problem statement tells you how to work it. You need to convert speed from miles per hour to feet (or inches) per second.
  90 mi/h = (90·5280 ft)/(3600 s) = 132 ft/s = (132·12 in)/s = 1584 in/s
__
23. The time it takes for the ball to travel 60.5 ft is ...
   time = distance/speed
   time = (60.5 ft)/(132 ft/s) = 0.4583 s
It takes 458.3 milliseconds to reach home plate.
__
24. time = distance/speed
   time = (17 in)/(1584 in/s) = 0.0107 s
The ball is in the strike zone for 10.7 milliseconds.