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dolphi86 [110]
4 years ago
5

Use the area of the rectangle to find the area of the triangle. 10 ft

Mathematics
1 answer:
77julia77 [94]4 years ago
7 0

Answer: 15

Aka the first one

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5 Points
LekaFEV [45]

Answer:

1043.43

Step-by-step explanation:

6 0
3 years ago
A sno-cone machine priced at $139 is on sale for 20% off. What is the price of the sno-cone machine after the discount? *
lawyer [7]
So percents are just written as 20% = 0.2 so keep that in mind

139 divided by 0.2 is 95 , which would be the price after the discount :)

hope this helps!
give me brainliest
7 0
3 years ago
Dylan wants to buy both the tablet and
nignag [31]

Answer:

108$

Step-by-step explanation:

6 0
3 years ago
Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
3 years ago
A map has a scale of 1 in: 10 mi. On the map, the distance between two cities is 5 inches. What is the actual distance between t
Schach [20]
50 miles since 1 inch equals 10 miles and there's 5 inches that means 5x10=50
4 0
3 years ago
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