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1 year ago

12

Sonia makes a wooden frame around a square picture. The frame is made of four congruent trapezoids. The shorter base is 9 in, th

e longer base is 12 in, and the height is 1.5 in. What is the area of the picture frame?

1 answer:

sp2606 [1]1 year ago

8 0

answer

congruent trapezoide for one

0,5(9+12)×1,5=15,75

area of picture frame =4×15,75=63

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the length of a rectangle is 9 inches more than the width. the perimeter is 54 inches. Find the length and width of the rectangl

Keith_Richards [23]

W is width W+9 is length W+W+9=54 2w=45 45/2 W=22.5 Width is 22.5 length is 31.5

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2 years ago

Ninas dog eats 1/6 lb of dog food twice a day. If Nina buys a 20 lb bag of dog food, how many days will the bag feed her dog?

My name is Ann [436]

Answer:

<h2>60 days</h2>

Step-by-step explanation:

<h3>Step 1: First, since it is 1/6 pound twice a day, multiply by 2</h3>

1/6 x 2 = 1/3

<h3>Step 2: Divide 20 by 3 to get days that bag will feed the dog</h3>

20 ÷ 1/3 = 60

The bag will feed Nina's dog for 60 days.

I'm always happy to help :)

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3 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra

Stella [2.4K]

Answer:

The 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =114.1$ represent the sample mean 1

$\bar X_2 =129.9$ represent the sample mean 2

n1=5 represent the sample 1 size

n2=2 represent the sample 2 size

$s_1 =5.08$ sample standard deviation for sample 1

$s_2 =5.37$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =114.1-129.9=-15.8$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_1 +n_2 -1=5+5-2=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=\pm 2.31$

The standard error is given by the following formula:

$SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$

And replacing we have:

$SE=\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=3.306$

Confidence interval

Now we have everything in order to replace into formula (1):

$-15.8-2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-23.437$

$-15.8+2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-8.163$

So on this case the 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

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2 years ago

Given the relation shown in the table below :

Dafna1 [17]

Answer:

domain: -7, -1, 0, 1

Range: -1, 0, 1, 2, 7

Step-by-step explanation:

I don't know the drop-down menu choices so I can't answer that one for you sorry :(

But I hope this helps :)

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2 years ago