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Answer:
Output explanation to the given code can be defined as follows:
Explanation:
In A the output is 0
, It will return fork value of the child process that is 0. so, 0 is printed during child process.
In B the output is 2650
, in which the getpid() method returns the child process id value that is 2650.
In C the output is 140, As it is declared in key, all process have their own "value" copies. 20 are inserted during childhood, so 140 are written.
In D the output is 2650, its fork() method returns the child ID to the parent process. so the value 2650 is printed.
In E the output is 2600, Its getpid() method will returns parent process id that is equal to 2600.
In F the output is 120 Since the value is declared in primary, all process so their own "value" copies. 120 will be printed during process.
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The indices of the internal array elements that hold the remaining elements is c) 2 to 4
<h3>Calculations and Parameters:</h3>
For us to create a capacity of 10 for the queue, we would enqueue:
We would create a queue of capacity 10:
<h3>Queue q(10);</h3>
We add elements/enqueue 5 elements to the queue :
- q.queueEnqueue(10);
- q.queueEnqueue(5);
- q.queueEnqueue(8);
- q.queueEnqueue(9);
- q.queueEnqueue(2);
Printing this would give:
q. queueDisplay()
10, 5, 8, 9, 2
Next, we would remove elements/dequeue 2 elements from the queue :
q. queuedequeue();
q. queuedequeue();
Printing it would be:
q. queueDisplay()
8 ,9, 2
Observing this, the deletion/dequeue starts from the front/first index.
The remaining indices of the internal array elements are: 2, 3, 4 or 2 to 4
Read more about arrays and enqueue here:
brainly.com/question/24188935
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