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3 years ago

Just simply find the missing words for me I'll mark it brainliest

Mathematics

2 answers:

saul85 [17]3 years ago

6 0

Answer:

Wheres the question?

Step-by-step explanation:

kvv77 [185]3 years ago

5 0

Answer:

I found all of them except no.8 .

You might be interested in

What are the solutions of x^2-2x+10=0

saw5 [17]

There are a few ways to solve this, the simplest of which is probably factoring. Start by finding factors of C (10) that add up to be B (-2).

fac(10) { -10, 1 ; -5, 2 }

Well, there are no factors of 10 that can add to b - so we will use the quadratic formula.

(-b +- sqrt(b^2 - 4ac)) / 2a

where a = 1, b = -2, c = 10

b^2 - 4ac = (-2)^2 - 4(1)(10) = 4 - 40 = -36

-b +- sqrt(-36) / 2a

(2 +- sqrt(-36)) / 2

sqrt(-36)

sqrt(-1 * 36)

sqrt(-1) * sqrt(36)

i * 6

2 + 6i / 2 ; 1 + 3i

2 - 6i / 2 ; 1 - 3i

Solutions: 1 + 3i, 1 - 3i

8 0

3 years ago

Read 2 more answers

A parabola can be drawn given a focus of (4, -3) and a directrix of y=5 Write the equation of the parabola in any form.

Serggg [28]

Answer:

The equation of the parabola is (x - 4)² = -16(y - 1)

Step-by-step explanation:

The standard form of the equation of the parabola is (x - h)² = 4p(y - k), where

The vertex of the parabola is (h, k)

The focus is (h, k + p)

The directrix is at y = k - p

∵ The focus of the parabola is (4, -3)

∵ The focus is (h, k + p)

∴ h = 4

∴ k + p = -3 ⇒ (1)

∵ It has a directrix of y = 5

∵ The directrix of the parabola is y = k - p

∴ k - p = 5 ⇒ (2)

→ Add equations (1) and (2) to find k and p

∵ (k + k) + (p - p) = (-3 + 5)

∴ 2k + 0 = 2

∴ 2k = 2

→ Divide both sides by 2

∴ k = 1

→ Substitute the value of k in equation (1)

∵ 1 + p = -3

→ Subtract 1 from both sides

∴ 1 - 1 + p = -3 - 1

∴ p = -4

∵ The form of the equation of the parabola is (x - h)² = 4p(y - k)

→ Substitute the values of h, k, p in it

∴ (x - 4)² = 4(-4)(y - 1)

∴ (x - 4)² = -16(y - 1)

∴ The equation of the parabola is (x - 4)² = -16(y - 1)

3 0

3 years ago

Ms. Ayala conducted a survey and found that 2/5 of her students love to draw and 1/4 of those students loved to paint their draw

kaheart [24]

Answer:

Step-by-step explanation:

2/5 * 1/4 = 2/20 or 1/10

7 0

3 years ago

Find the average value of f(x, y = over the region, r, the triangle with vertices (0, 0, (0, 1 and (1, 1.

makkiz [27]

Can't be done without knowing what $f$ is...

But I can tell you that the average value of $f$ is given by

$\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}$

At the very least, we can compute the denominator, which is just the area of $R$ . You have

$\displaystyle\iint_R\mathrm dx\,\mathrm dy=\int_{x=0}^{x=1}\int_{y=x}^{y=1}\mathrm dy\,\mathrm dx=\int_0^1(1-x)\,\mathrm dx=\dfrac12$

so the average value will be

$2\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy$