-2 (t+4)= -2 (t)+-2 (4)= -2t-8
Answer:
1
Step-by-step explanation:
Answer:
csc
A
, as desired!
Step-by-step explanation:
cos
2
A
sin
A
+
sin
2
A
cos
A
,
=
cos
2
A
cos
A
+
sin
2
A
sin
A
sin
A
cos
A
,
=
cos
(
2
A
−
A
)
sin
A
cos
A
,
=
cos
A
sin
A
cos
A
,
=
1
sin
A
,
=
csc
A
, as desired!
Ok, first put in the -2 for each b. That gives:
|-4(-2)-8|+|-1(-(-2))^2|+2(-2)^3
Let's do each section.
The first section is |-4(-2)-8)|
-4 times -2 is 8, minus 8 is 0. The absolute value of 0 is still 0.
Now we move on to |-1(-(-2))^2)|
First we do exponents
-(-2) is 2, and 2^2 is 4. 4 times -1 is -4. The absolute value of -4 is 4
Now the last section, 2(-2)^3
Exponents first: (-2)^3 is -2 * -2 * -2, which is -8.
-8*2=-16.
0+4+(-16)=-12
